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xxMikexx [17]
3 years ago
14

This from ionic compounds escape room​

Chemistry
1 answer:
stira [4]3 years ago
4 0

Answer:

Fe2O3 - S

PbO2 - D

PbO - I

Fe2O - U

Fe(OH)3 - H

FeO2 - T

FeO - R

Pb2O - G

Pb(OH)2 - O

FeOH - N

Pb(OH)3 - A

Explanation:

In writing the formula of ionic compounds we consider the valency or oxidation state of each ion.

For instance, given the compound iron II oxide. The oxidation states of both iron and oxygen are +2 and -2 respectively. Ignoring the charges, this cancels out and we have FeO as the correct formula of the compound.

For Iron III oxide, the oxidation states of iron and oxygen are +3 and -2 respectively, the both atoms exchange charges. If we ignore the signs and write the exchanged numbers as subscripts we obtain the formula Fe2O3.

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Read 2 more answers
A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10
Alex17521 [72]

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8O_{2}  ⇒P_{4} O_{6} +P_{4} O_{10}

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=\frac{117.9}{31} =3.80

Moles of O_{2} =\frac{117.9}{31} =3.80

No. of moles of formed product are equal and is \frac{1}{8}th of mole of any of reactant.

Thus weight of  P_{4} O_{6} =\frac{3.80}{8}×220 ≈103.41

        weight of  P_{4} O_{10} =\frac{3.80}{8}×284 ≈133.48

4 0
3 years ago
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