The molecular formula is C₄H₈O.
We must <em>calculate the masses</em> of C, H, and O from the masses given.
Mass of C = 17.873 mg CO₂ × (12.01 mg C/44.01 mg CO₂) = 4.8774 mg C
Mass of H = 7.316 mg H₂O × (2.016 mg H/18.02 mg H₂O) = 0.818 48 mg H
Mass of O = Mass of compound - Mass of C - Mass of H
= (7.321 – 4.8774 – 0.818 48) mg = 1.6251 mg
Now, we must convert these <em>masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u> </u><em><u>m</u></em><u>/mg </u> <em><u>n</u></em><u>/mmol</u> <u> Ratio </u> <u>Integers</u>
C 4.877 4 0.406 11 3.9984 4
H 0.818 48 0.811 99 7.9944 8
O 1.625 1 0.101 57 1 1
The empirical formula is C₄H₈O.
The energy to vaporize the water at its normal boilng point (100°C) is the vaporization latent heat.
The vaporization latent heat of water is 2257 J/ g (you can find it in a textbook, tables or internet).
So, with 955 kJ you can vaporize this amount of water:
[995 kJ * 1000J/kJ ] / 2557 J /g = 389.13 g
Use the density to convert to volume: D = M / V => V = M / D
V = 389.13 g / 1.00 g / ml = 389.13 ml, which rounded to 3 significant figures is 389 ml
Answer: 389 ml