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2 years ago

Which crash caused a greater change in motion for the satellite explains why and how? Write at least 1 paragraph and use vocab.

Physics

2 answers:

Slav-nsk [51]2 years ago

8 0

I think crash one but I may be wrong

chubhunter [2.5K]2 years ago

6 0

Answer:

Explanation:

Crash one

im very sorry if it is wrong. I am DUMB!!

Good luck, stay safe, have a great rest of your day, God bless, and happy holidays! :)

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What are used to transfer electrical energy from a power plant all the way to a home? generators turbines power transformers pow

defon

Answer:

Power lines

Explanation:

Generators induce that current that runs the turbines

Turbines also induce currents from water waves that is transmitted.

Transformers change A.C to D.C or vice versa.

4 0

3 years ago

Which changes in an electric motor will make the motor stronger? Check all that apply. using a stronger permanent magnet using a

miv72 [106K]

Use stronger magnets
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push magnets closer to coil
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4 0

3 years ago

Read 2 more answers

A 2.0 µF capacitor is charged through a 50,000 ohm resistor. How long does it take for the capacitor to reach 90% of full charge

Nesterboy [21]

Answer:

0.23 s

Explanation:

First of all, let's find the time constant of the circuit:

$\tau=RC$

where

$R=50,000 \Omega$ is the resistance

$C=2.0\mu F=2.0\cdot 10^{-6}F$ is the capacitance

Substituting,

$\tau=(50,000 \Omega)(2.0\cdot 10^{-6}F)=0.1 s$

The charge on a charging capacitor is given by

$Q(t)=Q_0 (1-e^{-t/\tau} )$ (1)

where

$Q_0$ is the full charge

we want to find the time t at which the capacitor reaches 90% of the full charge, so the time t at which

$Q(t)=0.90 Q_0$

Substituting this into eq.(1) we find

$0.90 Q_0 = Q_0 (1-e^{-t/\tau})\\0.90=1-e^{-t/\tau}\\e^{-t/\tau}=1-0.90=0.10\\-\frac{t}{\tau}=ln(0.10)\\t=-\tau ln(0.10)=(0.1 s)ln(0.10)=0.23 s$

4 0

3 years ago

And are facing each other of the two and the friend are on the separate more you when the moving. Your friend weighs a lot on yo

puteri [66]

Buddy, I think you need to evaluate your question and fix it. Because it's not making any sense, whatsoever.

7 0

3 years ago

After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38

ddd [48]

Answer:

64.2 m/s

Explanation:

We are given that

Speed ,v=38 m/s

We have to find the maximum speed when his car reach on flat ground.

Using dimensional analysis

$F_{res}\propto v^2$

If 35% acceleration reduced by F(res) at 38 m/s

Then, 100% acceleration can be reduced by F(res) at v' m/s

$\frac{F_1}{F_2}=\frac{v^2}{v'^2}$

$v'^2=\frac{F_2}{F_1}v^2$

$v'=v\sqrt{\frac{F_2}{F_1}}$

Substitute the values

$v'=38\times \sqrt{\frac{100}{35}}$

$v'=64.2 m/s$

Hence, the maximum speed when his car can reach on flat ground=64.2 m/s

3 0

2 years ago