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2 years ago

Which crash caused a greater change in motion for the satellite explains why and how? Write at least 1 paragraph and use vocab.

Physics

2 answers:

Slav-nsk [51]2 years ago

8 0

I think crash one but I may be wrong

chubhunter [2.5K]2 years ago

6 0

Answer:

Explanation:

Crash one

im very sorry if it is wrong. I am DUMB!!

Good luck, stay safe, have a great rest of your day, God bless, and happy holidays! :)

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PLEASE HURRYYYY!!!<br><br> Explain how you read measurements in a graduated cylinder?

fredd [130]

Answer:

Reading a Graduated Cylinder

Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.....

hope it helps....

5 0

9 months ago

When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ

Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

we know here that force

force = k × x .........1

so force = mg = 0.35 (9.8) = 3.43 N

3.43 = k × 0.12

k = 28.58 N/m

so period of oscillations is

period of oscillations = 2π × $\sqrt{\frac{m}{k} }$ ................2

put here value

period of oscillations = 2π × $\sqrt{\frac{0.35}{28.58} }$

period of oscillations = 0.6953

so period of oscillations is 0.695 second

4 0

3 years ago

Could anyone help with number 9?

Alisiya [41]

The answer would be A

3 0

2 years ago

You hang a 350 gram mass on a spring and its displaced 0.5 cm. Its spring constant is

Keith_Richards [23]

Answer:

Explanation:

kx = mg

k = mg/x

k = 0.350(9.81)/0.005

k = 686.7

k = 687 N/m

4 0

2 years ago

An 20-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around whic

Andrej [43]

Answer:

0.033815 m/s²

12.48810875 m

Explanation:

t = Time taken = 12 s

$\omega_f$ = Final angular velocity = 95 rpm

$\omega_i$ = Initial angular velocity = 64 rpm

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{95\times \frac{2\pi}{60}-64\times \frac{2\pi}{60}}{12}\\\Rightarrow \alpha=0.27052\ rad/s^2$

Tangential acceleration is given by

$a_t=\alpha r\\\Rightarrow a_t=0.27052\times 0.125\\\Rightarrow a_t=0.033815\ m/s^2$

The tangential acceleration of the pedal is 0.033815 m/s²

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{\left(95\times\frac{2\pi }{60}\right)^2-\left(64\times\frac{2\pi}{60}\right)^2}{2\times 0.27052}\\\Rightarrow \theta=99.90487\ rad$

Linear displacement would be $99.90487\times \frac{1}{2\pi}\times 2\pi\times 0.125=12.48810875\ m$

Length of chain that passes in the interval is 12.48810875 m

4 0

3 years ago