Science is a systematic enterprise that builds and organizes knowledge in the form of testable explanations and predictions about the universe. The earliest roots of science can be traced to Ancient Egypt and Mesopotamia in around 3000 to 1200 BCE.
As the air becomes warmer, heat<span> is transferred </span>between<span> molecules and kinetic</span>energy<span> is created which produces </span>thermal energy<span>. As the molecules move faster to transfer </span>heat<span>, the </span>temperature<span> also increases.</span>
In order for particles to perform a simple harmonic motion, we must follow the law of force of the form F = -kx, where x is the displacement of the object from the equilibrium position and k is the spring constant. The
force shown in <span>F = -kx is always the restoring force in the sense
that the particles are pulled towards the equilibrium position.
The
repulsive force felt when the charge q1 is pushed into another charge
q2 of the same polarity is given by Coulomb's law
F = </span><span>k *q1* q2 / r^2.
</span>It is clear that Coulomb's law is an inverse-square relationship. It does not have the same mathematical form as the equation <span><span>F = -kx.</span> Thus,
charged particles pushed towards another fixed charged particle of
the same fixed polarity do not show a simple harmonic motion when
released. Coulomb's law does not describe restoring force. When q1 is released, it just fly away from q2 and never returns.</span>
Answer:
P₃ > P₁ > P₂
Explanation:
To rank pressure of the given situation
a) we know
Pressure at height h below
P = ρ g h
density of salt water, ρ = 1029 kg/m³
P₁ = 1029 x 10 x 0.2
P₁ = 2058 Pa
b) density of fresh water, ρ = 1000 kg/m³
P₂ = 1000 x 10 x 0.2
P₂ = 2000 Pa
c) density of mercury, ρ = 13593 kg/m³
P₃ = 13593 x 10 x 0.05
P₃ = 6796.5 Pa
Rank of Pressures from highest to lowest
P₃ > P₁ > P₂
Answer:
≈ 6.68 m/s
Explanation:
A suitable formula is ...
vf^2 -vi^2 = 2ad
where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.
We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.
Then ...
vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s
vf ≈ 6.68 m/s
The ball hits the ground with a speed of about 6.68 meters per second.
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We assume the launch direction is either up or down.
