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Crank
3 years ago
5

What is the thermal energy least to greatest

Physics
1 answer:
mixer [17]3 years ago
7 0
1) turkey
2)coffee
3) ocean
4)ice burg
5) ice cube
that’s if you’re going hot to cold

hope this helps! please mark brainliest:)
You might be interested in
If the initial velocity of an object was -2 meters per second
Shalnov [3]
A :-) for this question , we should apply
a = v - u by t
Given - u = -2 m/s
v = -10 m/s
t = 16 sec
Solution -
a = v - u by t
a = -10 - -2 by 16
a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
2 x 4 = 8 )
a = 3 by 4
a = 0.75 m/s^2

.:. The acceleration is 0.75 m/s^2.
3 0
3 years ago
Please help this is due in an hour!!!!!
belka [17]

Answer:

1. Collision- the sudden, forceful coming together in direct contact of two bodies

2. Newton's third law of motion is<em> naturally applied to collisions between two objects</em>. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.

3. Momentum is the product of a moving object's mass and velocity. When two objects collide the total momentum before the collision is equal to the total momentum after the collision

6 0
3 years ago
A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile
tamaranim1 [39]

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

6 0
3 years ago
A lab technician uses laser light with a wavelength of 650 nmnm to test a diffraction grating. When the grating is 42.0 cmcm fro
Bingel [31]

Answer:

221 lines per millimetre

Explanation:

We know that for a diffraction grating, dsinθ =mλ where d = spacing between grating, θ = angle to maximum, m = order of maximum and λ = wavelength of light.

Since the grating is 42.0 cm from the screen and its first order maximum (m = 1) is at 6.09 cm from the center of the pattern,

tanθ = 6.09 cm/42.0 cm = 0.145

From trig ratios, cot²θ + 1 = cosec²θ

cosecθ = √((1/tanθ)² + 1) = √((1/0.145)² + 1) = √48.562 = 6.969

sinθ = 1/cosecθ = 1/6.969 = 0.1435

Also, sinθ = mλ/d at the first-order maximum, m = 1. So

sinθ = (1)λ/d = λ/d

Equating both expressions we have  

0.1435 = λ/d

d = λ/0.1435

Now, λ = 650 nm = 650 × 10⁻⁹ m

d = 650 × 10⁻⁹ m/0.1435

d = 4529.62 × 10⁻⁹ m per line

d = 4.52962 × 10⁻⁶ m per line

d = 0.00452962 × 10⁻³ m per line

d = 0.00452962 mm per line

Since d = width of grating/number of lines of grating

Then number of lines per millimetre = 1/grating spacing

= 1/0.00452962

= 220.77 lines per millimetre

≅ 221 lines per millimetre since we can only have a whole number of lines.

6 0
3 years ago
What is nuclear energy?
____ [38]

Answer: D. Energy released from atoms.

7 0
4 years ago
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