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g100num [7]
3 years ago
5

What is the most effective way to clean the science desks? Hypothesis:

Physics
1 answer:
lukranit [14]3 years ago
6 0
The most effective way to clean a science desks is to use a soapy water solution to clean tables using a clean disposable paper towel. Second, after cleaning the table surface with soap or detergent and rinsing with water, disinfect tables by using a diluted bleach water solution
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How much power does an average person input into their body
LekaFEV [45]

The average human generates around 100 watts in an average day

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4 years ago
The environment between the outer and inner nuclear membranes is most accurately referred to as the:
jenyasd209 [6]
C.Perinuclear Space
5 0
4 years ago
How many Medals in the Luge does the U.S. have?
Dafna11 [192]

Answer:

American athletes have won a total of 2,523 medals (1,022 of them gold) at the Summer Olympic Games and another 305 (105 of them gold) at the Winter Olympic Games, making the United States the most prolific medal-winning nation in the history of the Olympics.

Explanation:

Hope this helps! ^^

7 0
3 years ago
At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ > V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

W=\frac{p_0V_0-p_1V_1}{\gamma-1}

Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

pV^{\gamma}=k

where,

p = pressure

V = volume

\gamma=\frac{C_p}{C_V}

k = constant

Therefore, work done by the gas during expansion is,

W=\int\limits^{V_1}_{V_0} {p} \, dV

=k\int\limits^{V_1}_{V_0} {V^{-\gamma}} \, dV

=\frac{k}{\gamma -1} (V_0^{1-\gamma}-V_1^{1-\gamma})\\

(using pV^{\gamma}=k )

=\frac{p_0V_0-p_1V_1}{\gamma-1}

4 0
3 years ago
What is the equivalent resistance between points A and C if R1=1430, R2=1350, R3=1100, R4=1350, and R5=1150.
Marianna [84]

R1 + R4 = 1430 + 1350 = 2780 = R14    series combination of R1 & R4

R2 + R5 = 1350 + 1150 = 2500 = R25

The circuit has been reduced to 3 resistors in parallel

R314 = 2780 * 1100 / (2780 + 1100) = 788  this is the resistance of the parallel combination of R14 and R3

R31425 = 2500 * 788 / (2500 + 788) = 599 which is the equivalent of the circuit  - you can also use the formula for 3 resistors in parallel but this seems simpler

7 0
3 years ago
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