(1) an effective collision between reacting particles
Explanation:
In order for a chemical reaction to occur, an effective collision between reacting particles must always be.
- Based on the collision theory, for reactions to occur, there must be collisions between the reacting particles.
- It implies that the rate of reaction depends on the number of collision per unit time as well as the fraction of this collision that is successful or effective.
- For collisions to be effective, they must have adequate energy.
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<u>The three functions of the stem:</u>
- To support the leaves,
- To conduct water, and
- To conduct minerals to the leaves.
Answer:Physical changes occur when matter changes its chemical property but not its nature. Water turning into ice is an example of a physical change. Baking soda powder reacting to vinegar is an example of a chemical change Remember! Physical change: Properties remain the same are____physichal_________________ . ______ ___________substances are formed. List 5 signs of chemical change: List 5 examples of physical change: ______________________ ______________________
Explanation:
i tried to answer the most because of my proofile page it seems like i am in high school but i am iin 6th grade
Given the mass (in grams) of a reactant A, first divide this by the molar mass of A to get the number of moles of A. Then balance the chemical reaction, and divide the number of moles of A by the coefficient of A in the balanced reaction. Next, find the coefficient of the product (B) in the reaction, and multiply this by the result from the previous operation. Finally, multiply by the molar mass of B to get the final answer in grams of the product B.
<h3>
Answer:</h3>
0.50 mol SiO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
30 g SiO₂ (sand)
<u>Step 2: Identify Conversions</u>
Molar Mass of Si - 28.09 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of SiO₂ - 28.09 + 2(16.00) = 60.09 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig figs and round. We are given 2 sig figs.</em>
0.499251 mol SiO₂ ≈ 0.50 mol SiO₂