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nexus9112 [7]
3 years ago
9

Which of the following is true in regard to ions? A. A cation will hold a positive charge if it gains one or more electrons. B.

An ionized atom has a number of protons that is unequal to the number of electrons. C. Ions can carry only positive charges. D. Losing one or more electrons will turn an atom into an anion.
Chemistry
1 answer:
tigry1 [53]3 years ago
7 0

Answer:

B. An ionized atom has a number of protons that is unequal to the number of electrons.

Explanation:

For a neutral atom , the number of proton and electron is equal. An ionized atom has either loss or gain electron, thereby making the number of proton and electron unequal. The answer B is true because an ionized atom has either loss or gain electron to make the number of electron and proton unequal.

Option A is incorrect because a cations holds a positive charge when it loss one or more electron not when it gains one or more electron(s). Anions possess negative charge for gaining electron(s).

Option C is not true because ions can also carry negative charges and they are called anions.

Option D is false because losing one or more electron will turn an atom to a cations.

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Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
3 years ago
What isotope is used for a standard for other atomic masses?
sergeinik [125]
Though the ratio of any two atom's masses was the same on either scale, it was horribly confusing, so in 1961, a compromise was reached. Instead of using either Hydrogen, or Oxygen as the standard, the isotope of Carbon<span> with 6 </span>protons<span> and 6 neutrons in its nucleus (</span>Carbon-12<span>) was given a mass of exactly 12.</span>
3 0
3 years ago
Consider a general reaction A ( aq ) enzyme ⇌ B ( aq ) The Δ G ° ′ of the reaction is − 9.130 kJ ⋅ mol − 1 . Calculate the equil
Liula [17]

Answer:

K = 39.85

ΔG= -6.9 kJ/mol

Explanation:

Step 1: Data given

The ΔG°′ of the reaction is − 9.130 kJ/mol

Temperature = 25.0 °C = 298 K

Body temperature = 37.0 °C = 310K

the concentration of A is 1.9 M

the concentration of B is 0.80 M

Step 2: The reaction

A (aq) ⇌ B (aq)

Step 3:

ΔG° = -RT ln K

⇒with ΔG° = standard Gibbs free energy change = − 9.130 kJ/mol

⇒with R = the gas constant = 8.314 J/mol*K

⇒with T = the temperature = 298 K

⇒with K = the equilibrium constant = TO BE DETERMINED

− 9130 J/mol = - 8.314 * 298 * ln K

ln K = 3.685

K = e^3.685

K = 39.85

Step 4: The reaction at body temperature

ΔG= ΔG°  + RT ln [B]/[A]

⇒with ΔG° =  Gibbs free energy change

⇒with ΔG° = standard Gibbs free energy change = − 9130 J/mol

⇒with R = the gas constant = 8.314 J/mol*K

⇒with T = the temperature = 310 K

⇒with [A] = 1.9 M

⇒with [B] = 0.80 M

ΔG= -9130 J/mol + 8.314 J/mol*K * 310 K * ln (1.9/0.80)

ΔG= -9130 J/mol + 2229.4J/mol

ΔG=-6900.6 J/mol = -6.9 kJ/mol

6 0
3 years ago
Granite forms when magma cools slowly underground. Granite _____.
katrin [286]

Granite forms when magma cools slowly underground. Granite is an intrusive igneous rock. The answer is letter B. granite is composed mostly of quartz and feldspar with minor amounts of mica, amphiboles and other minerals.

3 0
2 years ago
What mass, in grams, of sodium bicarbonate, nahco3, is required to neutralize 1000.0 l of 0.350 m h2so4?
oksano4ka [1.4K]
Hello!

The net chemical equation between Sodium Bicarbonate and H₂SO₄ is the following one:

2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂

To calculate the amount of Sodium Bicarbonate needed to neutralize 1000 L of 0,350 M H₂SO₄ we'll need to use the following conversion factor, to go from the volume of H₂SO₄ to grams of Sodium Bicarbonate:

 1000 L H_2SO_4* \frac{0,350 moles H_2SO_4}{1 L}* \frac{2 moles NaHCO_3}{1 mol H_2SO_4}* \frac{84,007gNaHCO_3}{1molNaHCO_3} \\ \\ =58804,9 g NaHCO_3

So, to neutralize 1000 L  of 0,350 moles of H₂SO₄ you'll need 58804,9 grams of NaHCO₃
3 0
3 years ago
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