Answer:
82.28g
Explanation:
Given parameters:
Number of moles of hydrogen gas = 7.26 moles
Unknown:
Amount of ammonia produced = ?
Solution:
We have to write the balanced equation first.
N₂ + 3H₂ → 2NH₃
Now, we work from the known to the unknown;
3 moles of H₂ will produce 2 moles of NH₃
7.26 mole of H₂ will produce = 4.84 moles of NH₃
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Mass of NH₃ = number of moles x molar mass = 4.84 x 17 = 82.28g
Answer : The mass of produced from the reaction is, 0.651 grams.
Explanation :
The chemical reactions used are:
(1)
(2)
(3)
(4)
First we have to calculate the moles of
Molar mass of = 17 g/mol
Now we have to calculate the moles of
From the balanced chemical reaction 1, we conclude that:
As, 4 moles of react to give 4 moles of
So, 0.115 moles of react to give 0.115 moles of
Now we have to calculate the moles of
From the balanced chemical reaction 2, we conclude that:
As, 6 moles of react to give 1 moles of
So, 0.115 moles of react to give
moles of
Now we have to calculate the moles of
From the balanced chemical reaction 3, we conclude that:
As, 1 moles of react to give 4 moles of
So, 0.0192 moles of react to give
moles of
Now we have to calculate the moles of
From the balanced chemical reaction 4, we conclude that:
As, 4 moles of react to give 1 moles of
So, 0.0768 moles of react to give
moles of
Now we have to calculate the mass of
Molar mass of = 33.9 g/mole
Therefore, the mass of produced from the reaction is, 0.651 grams.