Na₂CO₃(s) → 2Na⁺(aq) + CO₃²⁻(aq)
The sodium carbonate formed from a strong base and a weak acid. Hydrolysis is subjected to the anion of a weak acid.
CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
pH>7 alkaline solution
2Na⁺ + CO₃²⁻ + 2H₂O ⇄ 2Na⁺ + 2OH⁻ + H₂CO₃
In a a cation-exchange resin, the outlet stream leaving the bed will contain
and
.
<h3>
What is cation-exchange resin?</h3>
- A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
- It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
- The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
- cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
- The most typical examples are water filtration and water softening.
To learn more about cation-exchange resin with the given link
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The right answer is noble gases.
The noble gases, or rare gases, are the chemical elements of group 18 (formerly "group VIIIA" or even "group 0") of the periodic table. These are helium He, neon 10Ne, argon 18Ar, krypton 36Kr, xenon 54Xe and radon 86Rn, the latter being radioactive.
This property means that they can not bind with other atoms to form molecules or lose electrons to transform into ions, hence their name noble or inert gases (they are not very active and do not do not mix). In nature, all elements "want" to become stable.
I did this when I was younger
Answer:
0.017 mol
Explanation:
CH3COOH - acetic acid - we can write as C2O2H4
From formula C2O2H4 we can see that ratio C: O = 2:2 = 1:1, so number of moles C and O are the same.
So if we have 0.017 mol C, we should have 0.017 mol O.