Answer:
1.3×10⁻³ M
Explanation:
Hello,
In this case, given the dissociation reaction of acetic acid:
We can write the law of mass action for it:
![Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BCH_3CO_2%5E-%5D%7D%7B%5BCH_3CO_2H%5D%7D)
Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change 
due to the dissociation extent, we are able to rewrite it as shown below:
Thus, via the quadratic equation or solve, we obtain the following solutions:
Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.
Regards.
3.0 × 10¹¹ RBC's (or) 3E11 RBC's
Solution:
Step 1: Convert mm³ into L;
As,
1 mm³ = 1.0 × 10⁻⁶ Liters
So,
0.1 mm³ = X Liters
Solving for X,
X = (0.1 mm³ × 1.0 × 10⁻⁶ Liters) ÷ 1 mm³
X = 1.0 × 10⁻⁷ Liters
Step 2: Calculate No. of RBC's in 5 Liter Blood:
As given
1.0 × 10⁻⁷ Liters Blood contains = 6000 RBC's
So,
5.0 Liters of Blood will contain = X RBC's
Solving for X,
X = (5.0 Liters × 6000 RBC's) ÷ 1.0 × 10⁻⁷ Liters
X = 3.0 × 10¹¹ RBC's
Or,
X = 3E11 RBC's
This reaction is called a composition reaction.
Ca2+ would bond to any element in a 1 to 1 ratio that had an equal and opposite charge.
Neon is a noble gas, and doesn’t form bonds m
Carbon isn’t typically found in ion state, but if it did, it would likely by C4+
Flouring in ionic state is F1-, so you would need 2 flourines to cancel the 2+ charge of Calcium
Then the only option left would be Oxygen which, when in ion form is found be 2-
Answer:
This self evaluation helps them to better his sport.
Explanation:
This is the right way to evaluate the performance of John because this sketch shows him the way he perform in the match. Due to this sketch he can better his performance and remove all the mistakes he had done in the match which results in better performance of John in the next match. This self evaluation helps them to better his sport and got new chances in order to select for a better club or national soccer team.
