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nadya68 [22]
3 years ago
10

Cost of production reports can also be used to compare the materials output quantity to the a.administrative staff input quantit

y. b.materials input quantity. c.conversion output quantity. d.total conversion for the period.
Chemistry
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

b.materials input quantity

Explanation:

A cost of production report shows the following:

  • total and unit costs transferred from preceding department
  • materials, labor , factory Overhead added by the department
  • unit costs added by the department
  • total and unit costs accumulated to the end of operations
  • the cost of beginning and ending work in process inventories
  • the cost transferred to the next department

A cost of production report determines periodic total and unit costs.

Either in the cost of production report or in the supporting schedule each item of material used is listed, every labor operation is shown separately,factory overhead components are noted individually, and a unit cost is derived for each item.

A Quantity Schedule Of Cost of Production report  shows the following

  • units started in process
  • units transferred to next department
  • units still in process
  • units lost in process

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Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

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  • When K_{c}; the reaction is reactant favored.
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For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

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Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.
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Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
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n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

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d

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