Sodium atom , potassium atom and cesium atom have the same group number which is group 1
To simplify our solution for this probelm we first assume that the gas we are dealing with is an ideal gas. Given that it is ideal we can proceed the solution using the formula: PV=nRT where P is pressure (203KPa), V is volume (20.0 L), n is moles (required), T is absolute temperature (373K) and R is the gas constant ( <span>8.31 l-kpa/m-k). Plug in the given to the respective variables and you should get 3.28 moles of the gas sample. </span>
Answer:
When baking soda or sodium Bicarbonate (NaHCo3) reacts with water carbonic acid is formed . The reaction is exothermic (so yes releases energy) that is heat (type of energy released) and Carbonic acid are produced. Carbonic acid is unstable so breaks up into carbon dioxide (which is the fizzy gas you see) and water forms.
Explanation:
Answer:
28.16 g/mol
Explanation:
From Graham's law;
Let the rate of diffusion of gas X be 1.25
Let the rate of diffusion of CO2 be 1
Molecular mass of gas X= M
Molecular mass of CO2 = 44g/mol
1.25/1=√44/M
(1.25/1)^2 = 44/M
1.5625 = 44/M
M= 44/1.5625
M= 28.16 g/mol
<span> a) AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) this is balanced chemical equation
</span><span>AgCl is the precipitate so we shall not split it
</span><span>Ag+(aq) + NO3 -(aq) + K+ (aq) + Cl-(aq) --> AgCl (s) + K+(aq) + NO3-(aq)
</span><span>Ag+ (aq) + Cl- (aq) ---> AgCl (s) after removing ions</span>
