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3 years ago

A5 kg frisbee is thrown from rest to a final speed of 12 m/s. What is the impulse of the frisbee?

Physics

1 answer:

lesya692 [45]3 years ago

3 0

Answer:

60kgm/s

Explanation:

Given parameters:

Mass of frisbee = 5kg

Final speed = 12m/s

Unknown:

Impulse of the frisbee = ?

Solution:

The impulse of the frisbee is the same as the change in momentum.

It is given as:

Impulse = mass (Final velocity - Initial velocity)

Impulse = 5(12 - 0) = 60kgm/s

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3 years ago

A bullet of mass 6.20 10-3 kg, moving at 1320 m/s impacts a tree stump and penetrates 11.00 cm into the wood before coming to re

sladkih [1.3K]

Answer:

F = -49.1 10³ N

Explanation:

Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant

$v_{f}$ ² = v₀² + 2 a x

Since the bullet is at rest, the final speed is zero

x = 11.00 cm (1 m / 100 cm) = 0.110 m

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2 years ago

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2 years ago

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PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A

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2 years ago