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polet [3.4K]
3 years ago
15

A positive test charge of 5.00 E-5 C is places in an electric field. The force on it is 0.751 N. The magnitude of the electric f

ield at the location of the test charge is
1.50 E4 N/C
1.52 E5 N/C
3.75 E4 N/C
3.75 E5 N/C
6.75 E4 N/C
Physics
2 answers:
zalisa [80]3 years ago
8 0

Explanation:

Charge=5.00 E-5

Force=0.751N

F=qE

0.751=5.00 E-5*E

E=1.502*10⁴

option a

Pavel [41]3 years ago
8 0

Answer:

\boxed{\mathrm{1.50 \: E^4  \: N/C}}

Explanation:

\displaystyle \mathrm{E=\frac{F_e}{q} }

\displaystyle \mathrm{Electric \: field \: strength \: (N/C)=\frac{Electric \: force \: (N)}{Charge \: (C)} }

\displaystyle \mathrm{E=\frac{0.751}{5.00\:  E^{-5}} }

\displaystyle \mathrm{E=\frac{0.751}{0.00005} }

\displaystyle \mathrm{E=15020}

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3 0
3 years ago
While sitting in your car by the side of a country road, you see your friend, who happens to have an identical car with an ident
Feliz [49]

Answer:

-6.49 m/s

Explanation:

This is doppler effect.

The equation is;

F_l = [(v + v_l)/(v + v_s)]F_s

Where;

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v is speed of sound

v_l is speed of listener

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F_s is frequency of the source of the sound

In this question, the source of the sound is the moving vehicle.

Thus;

F_l = F_beat + F_s

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So,

F_l = 5 + 260

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Since listener is sitting by car, thus; v_l = 0 m/s

Thus,from our doppler effect equation, let's make v_s the subject;

v_s = F_s[(v + v_l)/F_l] - v

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Thus;

v_s = 260[(344 + 0)/265] - 344

v_s = -6.49 m/s

This value is negative because the source is moving towards the listener

3 0
3 years ago
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