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2 years ago

What occurred while the surface rocks of the Moon were impacted, creating a fine dust?

2 answers:

8 0

Earth and a planetesimal collision occurred while the surface rocks of the moon were impacted, and was creating a fine dust. This is also called the giant.

Rom4ik [11]2 years ago

4 0

the moon became geologicly inactive

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How does the heat enhance the rate of chemical reaction ? Explain in short.

densk [106]

When the reactants are heated, the average kinetic energy of the molecules increases. This means that more molecules are moving faster and hitting each other with more energy. If more molecules hit each other with enough energy to react, then the rate of the reaction increases.

3 0

2 years ago

When an atom that has no charge loses two electrons, it becomes a

kicyunya [14]

Answer:

positive ion

Explanation:

due to the fact it loses electrons there is 2 more protons than electrons

3 0

3 years ago

a steel ball rolls horizontally off the edge of a tabletop that is 1.0 m high. it strikes the floor at a point 2.0 m horizontall

Sauron [17]

The ball in the air is for 0.319 sec.

The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

Calculate:-

H = ut + 1/2 gt²

Since the vertical initial velocity is 0.

H = 0 +gt²

t = $\sqrt{ \frac{H}{g}$

= $\sqrt{ \frac{1}{9.8}$

= 0.319 sec.

Learn more about projectile motion here:-brainly.com/question/10680035

#SPJ4

6 0

1 year ago

Summary about down hill on a bicycle story

Ne4ueva [31]

Answer:

The poem, Going Down the Hill on a Bicycle, written by Henry Charles Beeching describes the thrilling ride of a boy going downhill. ... The poet mentions how he lifts his feet from the pedals and keeps his hands still so that he would not lose his balance and fall off the bicycle, while it is dashing down the hill.

6 0

2 years ago

Two chargedparticles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged part

erica [24]

Answer:

Two possible points

x= 0.67 cm to the right of q1

x= 2 cm to the left of q1

Explanation:

Electrostatic Forces

If two point charges q1 and q2 are at a distance d, there is an electrostatic force between them with magnitude

$\displaystyle f=k\frac{q_1\ q_2}{d^2}$

We need to place a charge q3 someplace between q1 and q2 so the net force on it is zero, thus the force from 1 to 3 (F13) equals to the force from 2 to 3 (F23). The charge q3 is assumed to be placed at a distance x to the right of q1, and (2 cm - x) to the left of q2. Let's compute both forces recalling that q1=1, q2=4q and q3=q.

$\displaystyle F_{13}=k\frac{q_1\ q_3}{d_{13}^2}$

$\displaystyle F_{13}=k\frac{(q)\ (q)}{x^2}$

$\displaystyle F_{23}=k\frac{q_2\ q_3}{d_{23}^2}$

$\displaystyle F_{23}=k\frac{(q)(4q)}{(0.02-x)^2}$

$\displaystyle F_{23}=\frac{4k\ q^2}{(0.02-x)^2}$

Equating

$\displaystyle F_{13}=F_{23}$

$\displaystyle \frac{K\ q^2}{x^2}=\frac{4K\ q^2}{(0.02-x)^2}$

Operating and simplifying

$\displaystyle (0.02-x)^2=4x^2$

To solve for x, we must take square roots in boths sides of the equation. It's very important to recall the square root has two possible signs, because it will lead us to 2 possible answer to the problem.

$\displaystyle 0.02-x=\pm 2x$