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matrenka [14]
3 years ago
6

What is the difference in energy between a beta particle at rest and one traveling 0.35c?

Physics
1 answer:
monitta3 years ago
3 0

Answer:

They have a difference in energy of 35 eV.

Explanation:

The energy at rest of a particle is given by:

E_{R} = m_{0}c^2   (1)

Where m_{0} is the mass of the particle at rest and c is the speed of light.

Beta particles are high energy and high velocity electrons or positrons ejected from the nucleus of an atom as a consequence of a radioactive decay. Either if the beta particle is an electron¹ or a positron² it will have the same mass.

Hence, the mass of the beta particle at rest in equation (1) will be equal to the mass of an electron:

m_{e} = 9.1095x10^{-31} Kg

Replacing the values of m_{e} and c in equation (1) it is gotten:

E_{R} = (9.1095x10^{-31} Kg)(3.00x10^{8} m/s)^{2}

E_{R} = 8.19x10^{-14} Kg.m^{2}/s^{2}

But 1 J = Kg.m^{2}/s^{2}, therefore:

E_{R} = 8.19x10^{-14} J

It is better to express the rest energy in electronvolts (eV):

1eV = 1.60x10^{-19} J

8.19x10^{-14} J . \frac{1 eV}{1.60x10^{-19} J} ⇒ 511.875 eV

E_{R} = 511.875 eV

So the energy of the beta particle at rest is 511.875 eV.

Case for the one traveling at 0.35c:

Since it is traveling at 35% of the speed of light it is necessary to express equation (1) in a relativistic way, that can be done adding the Lorentz factor to it:

E = \frac{m_{0}c^{2}}{sqrt{1-\frac{v^{2}}{c^{2}}}}   (2)

Where v is the velocity of the particle (for this case 0.35c).

E = \frac{511.875 eV}{sqrt{1-\frac{(0.35c)^{2}}{c^{2}}}}

E = \frac{511.875 eV}{sqrt{1-\frac{0.1225c^{2}}{c^{2}}}}

E = \frac{511.875 eV}{sqrt{1-0.1225}}

E = \over{511.875 eV}{sqrt{0.8775}}

E = \over{511.875 eV}{0.936}

E = 546.875 eV

The difference in energy between the two particles can be determined using the relativistic form of the kinetic energy:

K = E – E_{R}  (3)

Where E is the energy of the particle traveling at 0.35c and E_{R} is the energy of the beta particle at rest.

K = 546.875 eV – 511.875 eV

K = 35 eV

They have a difference in energy of 35 eV.

Key terms:

¹Electron: Fundamental particle of negative electric charge.

²Positron: Is an electron with positive electric charge (similar to an electron in all its properties except in electric charge and magnetic moment).

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Because alkali metals are so reactive, they are found in nature only in combination with other elements. They often combine with group 17 elements, which are very “eager” to gain an electron.

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An electron is travelling in a straight line with a kinetic energy K = 1.60 x 10^-17J. What are (a) the magnitude and (b) the di
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(a) 1000 N/C

Explanation:

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distance, d = 10 cm = 0.1 m

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(a) The relation between the kinetic energy and the potential difference is

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V = \frac{1.6\times 10^{-17}}{1.6\times 10^{-19}}

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The relation between the electric field and the potential difference is given by

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100 = E x 0.1

E = 1000 N/C

(b) The force acting on the electron, F = q E

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So, F = -e x E

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An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
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Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

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Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

7 0
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