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matrenka [14]
3 years ago
6

What is the difference in energy between a beta particle at rest and one traveling 0.35c?

Physics
1 answer:
monitta3 years ago
3 0

Answer:

They have a difference in energy of 35 eV.

Explanation:

The energy at rest of a particle is given by:

E_{R} = m_{0}c^2   (1)

Where m_{0} is the mass of the particle at rest and c is the speed of light.

Beta particles are high energy and high velocity electrons or positrons ejected from the nucleus of an atom as a consequence of a radioactive decay. Either if the beta particle is an electron¹ or a positron² it will have the same mass.

Hence, the mass of the beta particle at rest in equation (1) will be equal to the mass of an electron:

m_{e} = 9.1095x10^{-31} Kg

Replacing the values of m_{e} and c in equation (1) it is gotten:

E_{R} = (9.1095x10^{-31} Kg)(3.00x10^{8} m/s)^{2}

E_{R} = 8.19x10^{-14} Kg.m^{2}/s^{2}

But 1 J = Kg.m^{2}/s^{2}, therefore:

E_{R} = 8.19x10^{-14} J

It is better to express the rest energy in electronvolts (eV):

1eV = 1.60x10^{-19} J

8.19x10^{-14} J . \frac{1 eV}{1.60x10^{-19} J} ⇒ 511.875 eV

E_{R} = 511.875 eV

So the energy of the beta particle at rest is 511.875 eV.

Case for the one traveling at 0.35c:

Since it is traveling at 35% of the speed of light it is necessary to express equation (1) in a relativistic way, that can be done adding the Lorentz factor to it:

E = \frac{m_{0}c^{2}}{sqrt{1-\frac{v^{2}}{c^{2}}}}   (2)

Where v is the velocity of the particle (for this case 0.35c).

E = \frac{511.875 eV}{sqrt{1-\frac{(0.35c)^{2}}{c^{2}}}}

E = \frac{511.875 eV}{sqrt{1-\frac{0.1225c^{2}}{c^{2}}}}

E = \frac{511.875 eV}{sqrt{1-0.1225}}

E = \over{511.875 eV}{sqrt{0.8775}}

E = \over{511.875 eV}{0.936}

E = 546.875 eV

The difference in energy between the two particles can be determined using the relativistic form of the kinetic energy:

K = E – E_{R}  (3)

Where E is the energy of the particle traveling at 0.35c and E_{R} is the energy of the beta particle at rest.

K = 546.875 eV – 511.875 eV

K = 35 eV

They have a difference in energy of 35 eV.

Key terms:

¹Electron: Fundamental particle of negative electric charge.

²Positron: Is an electron with positive electric charge (similar to an electron in all its properties except in electric charge and magnetic moment).

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4 0
3 years ago
What is the frequency of a transverse wave ?​
yuradex [85]

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The number of complete vibration or wave made in

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7 0
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A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it
kupik [55]

Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

80= 1/(2*0.9) √(T/0.0056)

144= √(T/0.0056)

Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

M=116.12/9.8

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4 0
3 years ago
A person pushes two boxes with a horizontal force F of magnitude of 100 N.
Monica [59]

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

  • m_A = 9\  kg

Mass of box B,

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Horizontal force,

  • F_{app} = 100 \ N

From the Newton's law,

→ F_{app} = (\frac{F_{app}}{m_A+m_B} )a

or,

→      a = \frac{F_{app}}{(m_A+m_B)}

Bu substituting the values, we get

→         = \frac{100}{9+2}

→         = \frac{100}{11}

→         9.10 \ m/s^2

We can see that between the two boxes, the action-reaction pair exist.

then,

→ F_{action-reaction} = m_b \ a

→                          =2\times 9.10

→                          = 18.2 \ N (magnitude)

Thus the above solution is appropriate.

 

Learn more about the magnitude here:

brainly.com/question/13545862

7 0
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adelina 88 [10]

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Speed of sound in a medium depends upon the density and elasticity of the medium.

If the elasticity of a medium is greater and the density of that medium is lower, sound will travel faster. Although density is also a factor but the major factor is Elasticity.

Hence, sound travel faster in solids than in liquids and even slower in gases due to elasticity difference.

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