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jolli1 [7]
3 years ago
6

Consider the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)

Chemistry
1 answer:
arsen [322]3 years ago
6 0

Answer:

K = 361.369

Explanation:

C2H4(g) + H2O(g) → CH3CH2OH(g)

∴ ΔG°f(298.15K) CH3CH2OH(g) = - 174.8 KJ/mol

∴ ΔG°f(298.15) C2H4(g) =  68.4 KJ/mol

∴ ΔG°f(298.15) H2O(g) = - 228.6 KJ/mol

⇒ ΔG°f(298.15) = - 174.8 - ( - 228.6 + 68.4 ) = - 14.6 KJ/mol

  • K = e∧(-ΔG°f / RT)

∴ R = 8.314 E-3 KJ/mol.K

∴ T = 298.15 K

⇒ K = e∧(-(-14.6)/((8.314 E-3)(298.15)))

⇒ K = e∧(5.889)

⇒ K = 361.369

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3 years ago
If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
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he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
2 years ago
if the lightbulb receives 100 J of electrical energy, and gives off 75 energy, how much heat (thermal energy away from the light
oksano4ka [1.4K]

Answer:

Amount of heat energy released by light bulb = 25 joules

Explanation:

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Energy receive by light bulb = 100 Joules

Energy released by light bulb as light energy = 75 Joules

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Amount of heat energy released by light bulb

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We know that, energy is neither be created nor destroys

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Using Law of conservation of energy

Energy receive by light bulb = Energy released by light bulb as light energy + Amount of heat energy released by light bulb

100 = 75 + Amount of heat energy released by light bulb

Amount of heat energy released by light bulb = 100 - 75

Amount of heat energy released by light bulb = 25 joules

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3 years ago
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