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erastovalidia [21]
2 years ago
8

IF YOU KNOW THE REST OF THE TEST'S ANSWERS PLEASE SHARE

Chemistry
2 answers:
Serjik [45]2 years ago
5 0

The phrase that correctly defines chemical equilibrium is a state in which the forward and reverse reactions are proceeding at equal rates

<h3>What is a Chemical equilibrium?</h3>

A Chemical equilibrium refers to the state of a chemical system at which a constant concentration of products and reagents is present.

A Substance turnover occurs only on the particle level which is the reason that chemical equilibrium is also referred to as dynamic equilibrium."

Therefore, the Option B is correct.

Read more about Chemical equilibrium

<em>brainly.com/question/5081082</em>

Semenov [28]2 years ago
3 0

Answer:

B. a state in which the forward and reverse reactions are proceeding at equal rates

Explanation:

"Chemical equilibrium is the state of a chemical system at which a constant concentration of products and reagents is present. Reactions, which take place in homogeneous solutions, seem to have come to rest because no changes in concentrations of the participating substances can be determined. Substance turnover occurs only on the particle level, which is why chemical equilibrium is also referred to as dynamic equilibrium."

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Density = Mass/Volume

19.2/25.7

= 0.747 or 0.75

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What substance cannot be broken down by chemical change
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Potassium is the simplest form of matter and therefore can not be broken down by chemical change.

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The following reactions can be used to prepare samples of metals. Determine the enthalpy change under standard state conditions
mamaluj [8]

Answer:

a) 62.1 kJ/mol

b) 2.82 kJ/mol

c) 270.91 kJ/mol

d) -851.5 kJ/mol

Explanation:

The enthalpy change for a reaction in standard conditions (ΔH°rxn) can be calculated by:

ΔH°rxn = ∑n*ΔH°f, products - ∑n*ΔH°f, reagents

Where n is the number of moles in the stoichiometry reaction, and ΔH°f is the enthalpy of formation at standard conditions. ΔH°f = 0 for substances formed by only a single element. The values can be found in thermodynamics tables.

a) 2Ag₂O(s) → 4Ag(s) + O₂(g)

ΔH°f, Ag₂O(s) = -31.05 kJ/mol

ΔH°rxn = 0 - (2*(-31.05)) = 62.1 kJ/mol

b) SnO(s) + CO(g) → Sn(s) + CO₂(g)

ΔH°f,SnO(s) = -285.8 kJ/mol

ΔH°f,CO(g) = -110.53 kJ/mol

ΔH°f,CO₂(g) = -393.51 kJ/mol

ΔH°rxn = [-393.51] - [-110.53 - 285.8] = 2.82 kJ/mol

c) Cr₂O₃(s) + 3H₂(g) → 2Cr(s) + 3H₂O(l)

ΔH°f,Cr₂O₃(s) = -1128.4 kJ/mol

ΔH°f,H₂O(l) = -285.83 kJ/mol

ΔH°rxn = [3*(-285.83)] - [( -1128.4)] = 270.91 kJ/mol

d) 2Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2Fe(s)

ΔH°f,Fe₂O₃(s) = -824.2 kJ/mol

ΔH°f,Al₂O₃(s) = -1675.7 kJ/mol

ΔH°rxn = [-1675.7] - [-824.2] = -851.5 kJ/mol

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