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2 years ago

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2 answers:

5 0

The phrase that correctly defines chemical equilibrium is a state in which the forward and reverse reactions are proceeding at equal rates

<h3>What is a Chemical equilibrium?</h3>

A Chemical equilibrium refers to the state of a chemical system at which a constant concentration of products and reagents is present.

A Substance turnover occurs only on the particle level which is the reason that chemical equilibrium is also referred to as dynamic equilibrium."

Therefore, the Option B is correct.

Read more about Chemical equilibrium

<em>brainly.com/question/5081082</em>

Semenov [28]2 years ago

3 0

Answer:

B. a state in which the forward and reverse reactions are proceeding at equal rates

Explanation:

"Chemical equilibrium is the state of a chemical system at which a constant concentration of products and reagents is present. Reactions, which take place in homogeneous solutions, seem to have come to rest because no changes in concentrations of the participating substances can be determined. Substance turnover occurs only on the particle level, which is why chemical equilibrium is also referred to as dynamic equilibrium."

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Answer:

Sodium Fluoride F 18 Injection is a positron emitting radiopharmaceutical, no-carrier added.

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3 years ago

Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance

GrogVix [38]

Answer:

Coefficient of $C_3H_8O_2=3$

Coefficient of $KMnO_4$ =8

Explanation:

We are given that a reaction in which $C_3H_8O_2$ reacts with $KMnO_4$

We have to find the coefficient of each reactants in balanced reaction

$3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O$

Coefficient is defined the constant value multiplied with a reactant in a reaction.

Coefficient of $C_3H_8O_2$ =3

Coefficient of $KMnO_4=8$

Coefficient of $C_3H_2O_4K_2=3$

Coefficient of $MnO_2=8$

Coefficient of $H_2O=8$

Coefficient of KOH=2

Hence, Coefficient of $C_3H_8O_2=3$ and coefficient of $KMnO_4=8$

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