Question

Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coefficient of kinetic friction between the player and the ground is 0.70. His speed at the start of the slide is 8.23 m/s. I a) Calculate his acceleration during the slide. b) How long (in time) does he slide until he stops?​

Answer 1

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

How to determine the force of friction

• Mass (m) = 81.5 Kg
• Coefficient of friction (μ) = 0.7
• Acceleration due to gravity (g) = 9.8 m/s²
• Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
• Frictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

A. How to determine the acceleration

• Mass (m) = 81.5 Kg
• Frictional force (F) = 559.09 N
• Acceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

B. How to determine the time

• Initial velocity (u) = 8.23 m/s
• Final velocity (v) = 0 m/s
• Decceleration (a) = -6.86 m/s²
• Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

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