Answer:
The answer to your question is: t = 2.5 s
Explanation:
Data
vo = 30 m/s
a = -12 m/s2
t = ?
vf = 0 m/s
Formula
vf = vo + at
Substitution
0 m/s = 30 + (-12)t
Solve it for t -30 = -12t
t = -30 / -12
t = 30/12 = 15/6 = 5/2
t = 2.5 s
Answer:
I think the the answer is creating and layout and template style ( C )
Explanation:
I did it before and i was checking my notes and i wrote that down , Hope this Helps :)
E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.
The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O.
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.
The product is 2-methyl-2-butene.
Given:
The mass of the copper cylinder is: m = 76.8 g = 0.0768 kg
The change in the temperature is: T = 86.5 deg C - 19.5 deg C = 67 deg C
The specific heat is: c = 0.092 cal/g.C
To find:
Heat energy needed to heat the copper cylinder.
Explanation:
The specific heat is defined as the amount of heat energy needed to raise the temperature of a substance by one degree celcius.
The expression relating heat Q, mass m, specific heat c and temperature difference T is:

Substitute the values in the above equation, we get:

Final answer:
473.40 calories of heat is required to heat the copper cylinder.
Answer: 
Explanation:
Given
Mass of hockey puck 
Initial velocity of hockey puck is 
First a horizontal force of
is applied to the right for 
acceleration associated with it is

Using equation of motion i.e.

(b) When a force of
is applied for 0.05s
Using equation of motion i.e.
