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melisa1 [442]
2 years ago
10

Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coef

ficient of kinetic friction between the player and the ground is 0.70. His speed at the start of the slide is 8.23 m/s. I a) Calculate his acceleration during the slide. b) How long (in time) does he slide until he stops?​
Physics
1 answer:
Alex777 [14]2 years ago
4 0

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

<h3>How to determine the force of friction</h3>
  • Mass (m) = 81.5 Kg
  • Coefficient of friction (μ) = 0.7
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
  • Frictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

<h3>A. How to determine the acceleration</h3>
  • Mass (m) = 81.5 Kg
  • Frictional force (F) = 559.09 N
  • Acceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

<h3>B. How to determine the time </h3>
  • Initial velocity (u) = 8.23 m/s
  • Final velocity (v) = 0 m/s
  • Decceleration (a) = -6.86 m/s²
  • Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

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A car is travelling at a speed of 30 m/s. It decelerates at a rate of 12 m/s^2. Calculate the time taken for the car to come to
user100 [1]

Answer:

The answer to your question is: t = 2.5 s

Explanation:

Data

vo = 30 m/s

a = -12 m/s2

t = ?

vf = 0 m/s

Formula

vf = vo + at

Substitution

                              0 m/s = 30 + (-12)t

Solve it for t           -30 = -12t

                              t = -30 / -12

                              t =  30/12  = 15/6 = 5/2

                              t = 2.5 s                              

8 0
3 years ago
Read 2 more answers
Marked as brainiest if correct
Naily [24]

Answer:

I think the the answer is creating and layout and template style     ( C )

Explanation:

I did it before and i was checking my notes and i wrote that down , Hope this Helps :)

7 0
3 years ago
Complete the electron-pushing mechanism for the e1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid.
Sav [38]
E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.

The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O. 
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.

The product is 2-methyl-2-butene.


6 0
4 years ago
Read 2 more answers
A copper cylinder has a mass of 76.8 g and a specific heat of 0.092 cal/g.C. It is heated to 86.5 degrees C from 19.5 degrees C.
Sladkaya [172]

Given:

The mass of the copper cylinder is: m = 76.8 g = 0.0768 kg

The change in the temperature is: T = 86.5 deg C - 19.5 deg C = 67 deg C

The specific heat is: c = 0.092 cal/g.C

To find:

Heat energy needed to heat the copper cylinder.

Explanation:

The specific heat is defined as the amount of heat energy needed to raise the temperature of a substance by one degree celcius.

The expression relating heat Q, mass m, specific heat c and temperature difference T is:

Q=mcT

Substitute the values in the above equation, we get:

\begin{gathered} Q=76.8\text{ g}\times0.092\text{ Cal/g.C}\times67\text{ deg C} \\  \\ Q=473.40\text{ Cal} \end{gathered}

Final answer:

473.40 calories of heat is required to heat the copper cylinder.

6 0
1 year ago
0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t 0, the puck is moving to the right at 3.00 m/s.
balandron [24]

Answer: (a)10.812\ m/s\ (b)\ 0.75\ m/s\ \text{left}

Explanation:

Given

Mass of hockey puck m=0.160\ kg

Initial velocity of hockey puck is u=3\ m/s

First a horizontal force of 25\ N is applied to the right for 0.05\ s

acceleration associated with it is

\Rightarrow a=\dfrac{25}{0.160}\\\\\Rightarrow a=156.5\ m/s^2

Using equation of motion i.e.

\Rightarrow v=u+at\\\Rightarrow v=3+156.25\times 0.05\\\Rightarrow v=3+7.812\\\Rightarrow v=10.812\ m/s

(b) When a force of 12\ N is applied for 0.05s

Using equation of motion i.e.

\Rightarrow v=3-\dfrac{12}{0.160}\times 0.05\\\\\Rightarrow v=3-75\times 0.05\\\Rightarrow v=3-3.75\\\Rightarrow v=-0.75\ m/s\\\Rightarrow v=0.75\ \text{towards left}

6 0
3 years ago
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