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CaHeK987 [17]
3 years ago
9

A 0.5 kg mass moving East with a velocity of 8 m/s is acted upon by a force of 20 N for 2.0 sec.

Physics
1 answer:
Andrej [43]3 years ago
7 0

Answer:b

Explanation:

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Guys please helpp!!!!1
Setler79 [48]

Answer:

Position A/Position E

K = E, U = 0

Position B/Position D

K = (1-x)\cdot E, U = x\cdot E, for 0 < x < 1

Position C

K = 0, U = E

Explanation:

Let suppose that ball-Earth system represents a conservative system. By Principle of Energy Conservation, total energy (E) is the sum of gravitational potential energy (U) and translational kinetic energy (K), all measured in joules. In addition, gravitational potential energy is directly proportional to height (h) and translational kinetic energy is directly proportional to the square of velocity.

Besides, gravitational potential energy is increased at the expense of translational kinetric energy. Then, relative amounts at each position are described below:

Position A/Position E

K = E, U = 0

Position B/Position D

K = (1-x)\cdot E, U = x\cdot E, for 0 < x < 1

Position C

K = 0, U = E

3 0
3 years ago
Is it ever possible for the work done by friction to increase the kinetic energy of an object?
sweet-ann [11.9K]
Honestly I don’t really know in my opinion

3 0
3 years ago
A man weighing 700 N lifts a 50.0 N object 2.0 m high. He uses a lever and with a force of 10.0 N. What is the resistance force
umka21 [38]
For the answer to the question above, asking what is the resistance force if a man weighing 700 N lifts a 50.0 N object 2.0 m high. He uses a lever and with a force of 10.0 N. 
we can use the formula below for calculating lever
<span>thus, Le / Lr = 50 / 10 = 5 </span>

5 0
3 years ago
A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300
adell [148]

Answer:

   v = 306.76 Km/h

Explanation:

given,

height of the aircraft = 3000 m

differential pressure reading = 3300 N/m²

density of air = 0.909 Kg/m³

speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

          \dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}

where ρ is the density of the air at 3000 m

          v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}

          v= \sqrt{\dfrac{2 \times 3300}{0.909}}

          v = \sqrt{7260.726}

                 v = 85.21 m/s

          v= 85.21 \times \dfrac{3600}{1000}

                 v = 306.76 Km/h

4 0
3 years ago
Measure the distance from the drop point in Brazil to the drop point in Angola. Use that number in your calculation. Given that
klemol [59]

To develop this point we will start by finding the approximate coordinates of the points that were connected at the time of the Pangaea between Brazil and Angola. These coordinates are presented below.

1 . Brazil - Latitude: 18 0 07’ 55.56” S Longitude: 39 0 35’ 14.50” W 2.

Angola - Latitude: 9 0 08’ 50.02” S Longitude: 13 0 02’ 32.11” E

Using a tool for calculating distances between these two points we will notice that its distance is 576,155,570.12 cm

Applying the equation given in the statement we will have to,

v = \frac{x}{t} \rightarrow v = Velocity, x = Distance, t = Time

200,000,000 years have passed and the movement was previously found, so the speed of travel is,

v = \frac{576,155,570.12cm}{200.000.000 years}

v = 2.88 cm/year

Therefore the velocity is 2.88 cm per year.

6 0
3 years ago
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