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alexdok [17]
3 years ago
12

I’ll give brainliest and 10 points

Physics
1 answer:
schepotkina [342]3 years ago
4 0
I think it is D. I hope this helps
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A series RCL circuit consists of a 50 Ω resistor, 500 Ω capacitor, and a 500 Ω inductor. What is the angle of impedance?
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Answer:

Zero

Explanation:

here, the inductive reactance and the capacitive reactance is same, so this is the condition for resonance.

In the condition for resonance,

the circuit and the voltage in the circuit is in the same phase and the impedance of the circuit is minimum which is equal to the resistance of the circuit.

The phase angle is given by

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What is the relationship in which the ratio of the manipulated variable and the responding variable is constant?
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That's a 'direct' or 'proportional' variation.

The variables are related by the equation      Y = K X .

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3 years ago
A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe
bearhunter [10]

Answer:

t=L/V_1

Explanation:

<u>solution:</u>

Let E be an observer, and B a second observer traveling with velocity V_{BE}  as measured by E. If E measures the velocity of an object A as V_{AE}  then B will measure A velocity as

V_{AB} = V_{AE} -  V_{BE}  

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

V_{MW} = V_{ME} -  V_{WE}  

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V_2=V_{MW}

The time required for the woman, traveling at constant speed V_1 relative to the ground, to travel distance L relative to the ground is :

t=L/V_1

 

3 0
4 years ago
The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in
lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m

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\tau=0.5\ N-m

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