Question

Volume of a cone = r²h,

Answer 1

Answer:

7.5 m           457.5$\pi$ $m^{2}$

Step-by-step explanation:

First, visualize the original cone and the smaller cone as overlapping similar triangles. The scale factor of the original cone to the smaller cone is 50:40, so if the smaller cone has a radius of 6 m, then the radius of the original cone would be 7.5 m.

The volume of the frustum is the volume of the original cone minus the volume of the smaller cone. The formula for the volume of a cone is V = $\frac{1}{3} \pi r^{2}h$.

Original Cone = $\frac{1}{3} \pi r^{2}h$ = $\frac{1}{3} \pi *7.5^{2}*50$ = 937.5$\pi$

Smaller Cone = $\frac{1}{3} \pi r^{2}h$ =  $\frac{1}{3} \pi *6^{2}*40$ = 480$\pi$

Frustum = 937.5$\pi$ - 480$\pi$ = 457.5$\pi$