Who knows how to do this?
1 answer:
Answer:
1) F = 8.789 10² N, 2) F = 1.5 10⁴ N
Explanation:
We can solve this exercise using Coulomb's law
F =
Knowing that charges of the same sign repel
let's apply this equation to our case
1) the charges are q = - 0.0025 C and the distance between them r = 8 m
we calculate
F = 9 10⁹ 0.0025 0.0025 /8²
F = 8.789 10² N
as the two charges are of the same sign the force is repulsive
2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m
we calculate
F = 9 10⁹ 0.004 0.003 / 3²
F = 1.5 10⁴ N
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Explanation:
Given parameters:
Initial velocity = 72km/hr
Final velocity = 0km/hr
Time taken = 25s
Unknown:
Acceleration = ?
Solution:
To solve this problem, convert km/hr to m/s;
1000m = 1km
3600s = 1hr
72km/hr;
1km/hr = 0.278m/s
72km/hr = 0.278 x 72 = 20.02m/s
Acceleration is the change in velocity divided by the time taken;
Acceleration =
Acceleration = = -0.8m/s
The car is actually decelerating at a rate of 0.8m/s
Answer:
c.
Explanation:
Initial velocity of cheetah,u=1 m/s
Time taken by cheetah =4.8 s
Final velocity of cheetah,v=28 m/s
We have to find the acceleration of this cheetah.
We know that
Acceleration,
Where v=Final velocity of object
u=Initial velocity of object
t=Time taken by object
Using the formula
Then, we get
Acceleration, a=
Acceleration=
Hence, the acceleration of cheetah=