Average velocity is calculated as the division of displacement and change in time so the answer would be 804 km/36000 s=0.02 m/s
Answer:
C The launcher will fall off the platform and land D/2 to the left of the platform because the launcher is twice the mass of the ball.
Explanation:
The figure is missing: you can find it in attachment.
We can apply the law of conservation of momentum to check that the launcher will leave the platform with a speed which is half the speed of the ball. In fact, the total initial momentum is zero:

while the total final momentum is:

where
is the mass of the launcher
is the mass of the ball
is the velocity of the launcher
is the velocity of the ball
Since the total momentum must be conserved,
, so

Therefore we find

which means that the launcher leaves the platform with a velocity which is half that of the ball, and in the opposite direction (to the left).
Since the distance covered by both the ball and the launcher only depends on their horizontal velocity, this also means that the launcher will cover half the distance covered by the ball before reaching the ground: therefore, since the ball covers a distance of D, the launcher will cover a distance of D/2.
Answer: yes u can use a 6.75 when measuring the pencil
Answer:
0.5 m.
Explanation:
From the question given above, the following data were obtained:
Force (F) = 5 N
Work done (W) = 2.5 J
Distance (s) =?
Workdone is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:
Work done (W) = Force (F) × Distance (s)
W = F × s
With the above formula, we can obtain the distance to which the book has moved as follow:
Force (F) = 5 N
Work done (W) = 2.5 J
Distance (s) =?
W = F × s
2.5 = 5 × s
Divide both side by 5
s = 2.5/5
s = 0.5 m
Therefore, the book moved 0.5 m when the force was applied.