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Vladimir79 [104]
3 years ago
5

A metal rod with a length of 25.0 cm lies in the xy-plane and makes an angle of 37.5 ∘ with the positive x-axis and an angle of

52.5 ∘ with the positive y-axis. The rod is moving in the +x-direction with a speed of 6.80 m/s . The rod is in a uniform magnetic field B⃗ =(0.130T)i^−(0.290T)j^−(0.0800T )k^.
What is the magnitude of the emf induced in the rod?
Physics
1 answer:
pashok25 [27]3 years ago
5 0
We are given with the following:
L = 25 cm
θx = <span>37.5</span>°<span>
</span>θy = 52.5°
vx = 6.8 m/s
B = 0.13i - 0.29j - 0.08k

And we are asked for the emf induced in the rod
E = B L v
Substitute the values for B and L into the equation. For v, use the given velocity along x and the angles to convert it to vector form. Then, solve for E.
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