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Ber [7]
3 years ago
12

What is the formula for Chromium (III) Bisulfite?​

Chemistry
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

Cr2(SO4)3

Explanation:

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33.1 x 105 <br> What is the scientific notation
Sunny_sXe [5.5K]

Answer:

3475.5 or 6591/2

Explanation:

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3 years ago
Which of the following is an anion?
satela [25.4K]
A . O2- because it is a negatively charged ion
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3 years ago
How many grams of precipitate will be formed when 20.5 mL of 0.800 M
Anton [14]

Answer:

There will be formed 1.84 grams of precipitate (NaNO3)

Explanation:

<u>Step 1</u>: The balanced equation

CO(NO3)2 (aq) + 2 NaOH (aq) → CO(OH)2 (s) + 2 NaNO3 (aq)

<u>Step 2:</u> Data given

Volume of 0.800 M  CO(NO3)2 = 20.5 mL = 0.0205 L

Volume of 0.800 M NaOH = 27.0 mL = 0.027 L

Molar mass of NaNO3 = 84.99 g/mol

<u>Step 3:</u> Calculate moles of CO(NO3)2

Moles CO(NO3)2  = Molarity * volume

Moles CO(NO3)2  = 0.800 M * 0.0205

Moles CO(NO3)2 = 0.0164 moles

Step 4: Calculate moles NaOH

moles of NaOH = 0.800 M * 0.027 L

moles NaOH = 0.0216 moles

Step 5: Calculate limiting reactant

For 1 mole CO(NO3)2 consumed, we need 2 moles of NaOH to produce 1 mole of CO(OH)2 and 2 moles of NaNO3

NaOH is the limiting reactant. It will completely be consumed.

CO(NO3)2 is in excess. There willbe 0.0216 / 2 = 0.0108 moles of CO(NO3)2 consumed. There will remain 0.0164 - 0.0108 = 0.0056 moles of CO(OH)2

Step  6: Calculate moles of NaNO3

For 2 moles of NaOH consumed, we have 2 moles of NaNO3

For 0.0216 moles of NaOH, we have 0.0216 moles of NaNO3

Step 7: Calculate mass of NaNO3

mass of NaNO3 = moles of NaNO3 * Molar mass of NaNO3

mass of NaNO3 = 0.0216 moles * 84.99 g/mol = 1.84 grams

There will be formed 1.84 grams of precipitate (NaNO3)

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3 years ago
Is NaCi a metal or nonmetal
Kruka [31]
Hi , NaCl is basically salt , Na for sodium and Cl for chlorine , these elements make Sodium Chloride .The bond between them is ionic.
5 0
3 years ago
Read 2 more answers
What’s the answers to these?
nata0808 [166]

Answer:

0bervation

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cause it is

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