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Ber [7]
3 years ago
12

What is the formula for Chromium (III) Bisulfite?​

Chemistry
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

Cr2(SO4)3

Explanation:

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Which is not a property of minerals?<br><br> Streak<br><br> State<br><br> Luster <br><br> Hardness
kvv77 [185]

Streak is not a property of minerals.

6 0
3 years ago
Read 2 more answers
Lab: Applications of electromagnetic​
Pavlova-9 [17]

Answer:Not the same class but it will give u 100%

Explanation:

1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.  

To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.  

My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.  

2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.  

A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.  

3.  Some formulas I used were KE= ½ mv^2 and Ht v^2/2g. The first was to calculate the kinetic energy of an object, m=mass v=speed. Second was for finding out what height I needed to drop something to reach a certain speed, Ht=Height and g= Gravitational Acceleration of 9.8 m/s^2.  

I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.  

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.  

To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

7 0
2 years ago
What are stationary fronts?
goldfiish [28.3K]
A stationary front (or quasi-stationary front) is a weather front or transition zone between two air masses, when neither air mass is advancing into the other at a speed exceeding 5 knots (about 6 miles per hour or about 9 kilometers per hour) at the ground surface. On weather maps, it is shown by a solid line of alternating blue spikes pointing to the warmer air mass and red domes pointing to the colder air mass. If your talking about a weather front Hope this helped.
7 0
3 years ago
A student adds 200.0g of C7H6O3 to an excess of C4H6O3, this produces C9H8O4 and C2H4O2. Calculate the percent yield if 231 g of
kari74 [83]

Answer: Percent yield = 88%

Explanation:

Given data:

Mass of C₇H₆O₃ = 200.0 g

Actual yield of aspirin = 231 g

Percent yield  = ?

Solution:

Chemical equation:

C₇H₆O₃  + C₄H₆O₃      →       C₉H₈O₄ + C₂H₄O₂

Number of  moles of aspirin:

Number of moles = mass/molar mass

Number of moles = 200.0 g/ 138.12 g/mol

Number of moles =  1.45 mol

Now we will compare the moles of aspirin with C₇H₆O₃.

                         C₇H₆O₃           :           C₉H₈O₄

                              1                 :               1

                           1.45              :             1.45

Theoretical yield of aspirin:

Mass = number of moles × molar mass

Mass = 1.45 g × 180.158 g/mol

Mass = 261.23 g

Percent yield:

Percent yield =( actual yield / theoretical yield )× 100

Percent yield =  (231 g/ 261.23 g)× 100

Percent yield = 0.88 × 100

Percent yield = 88%

:

7 0
2 years ago
What is the molality of ethylene glycol, c2h4(oh)2, in a solution prepared from 2. 331×103 g of ethylene glycol and 2. 00×103 g
qaws [65]

Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

Ethylene Glycol is known as C₂H₄(OH)₂. It is added in water to prepare an Antifreeze solution.

Given,  

Mass of Ethylene Glycol = 2.331 × 10³ g = 2.331kg

Mass of Water = 2.00 × 10³ g

Since, Ethylene Glycol is in excess. Hence, it acts as a solvent and water acts as a solute.

We know, Molar Mass of Water = 18g

Hence, Moles of  Water = Given mass of water / Molar Mass of Water

⇒             Moles of  Water = 2000 / 18

⇒            Moles of  Water = 111.1

Molality is defined as the moles of solute present in a given solvent in kg.

∴ Molality = Moles of  Solute / Mass of Solvent (in kg)

Molality = Moles of  Water / Mass of Ethylene Glycol

⇒ Molality = 111.1 / 2.331

⇒ Molality = 47.6m

Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

Learn more about Molality here, brainly.com/question/17034043

#SPJ4

3 0
2 years ago
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