Answer:
10.85 g of water
Explanation:
First we write the balanced chemical equation
Then we calculate the number of moles of nitric acid produced
n(HNO3) =
According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:
mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g