Why does hydrochloric acid have a higher boiling point than diatomic fluorine? The stabilizing effect of dipole interactions in
2 answers:
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Answer:
0.011 mol/L
Explanation:
This can be solved with something called an ICE table.
I = initial
C = change
E = equilibrium
Initially, there is 0.04 M of N₂, 0.04 M of O₂, and 0 M of NO.
x amount of N₂ reacts. Since the stoichiometry is 1:1, x amount of O₂ also reacts. This produces 2x of NO.
After the reaction, there is 0.04-x of N₂, 0.04-x of O₂, and 2x of NO.
Here it is in table form:
Now we can use the equilibrium constant:
Kc = [NO]² / ( [N₂] [O₂] )
Substituting:
0.10 = (2x)² / ( (0.04 - x) (0.04 - x) )
Solving:
0.10 = (2x)² / (0.04 - x)²
√0.10 = 2x / (0.04 - x)
(√0.10) (0.04 - x) = 2x
(√0.10)(0.04) - (√0.10)x = 2x
(√0.10)(0.04) = 2x + (√0.10)x
(√0.10)(0.04) = (2 + √0.10)x
x = (√0.10)(0.04) / (2 + √0.10)
x = 0.0055
At equilibrium, the concentration of NO is 2x. So the answer is:
[NO] = 2x
[NO] = 0.011
The equilibrium concentration of NO is 0.011 mol/L.
If we consider a structure in which a carbon is bonded to two three carbon chains and a branched alkane then the branched alkane is a 2 carbon chain with a ethyl on Carbon 1 then the correct name of the structure is <u>4-(isopropyl)heptane. </u>
The two three carbon chains bonded to the carbon atom will form the parent chain of this structure and this chain will have 7 carbon atoms in it.
Since this chain is that of an alkane and it has no functional group attached so the root name will be heptane.
Now, we have to add a prefix by naming the branched alkyl chain. The branched chain has 3 carbon atoms in it with a methyl group on carbon 1.
So, this name of this group will be propyl.
The position of this propyl group is 4th on the parent chain so the full name of the structure will be 4-(isopropyl)heptane.
To know more of branched alkane here
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