Answer:
Ka2 values should be used in obtaining pKa2 in the Henderson–Hasselbalch equation
Explanation:
During first dissociation from H3PO4 to H2PO4-, ka1 will be used, and from H2PO4-to HPO4-, ka2 values will be used, hence a buffer solution containing H2PO4-and HPO4-will use ka2 in obtaining pKa2 in the Henderson–Hasselbalch equation.
Answer:
a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.
c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.
Explanation:
A buffer system is formed in 1 of 2 ways:
- A weak acid and its conjugate base.
- A weak base and its conjugate acid.
Determine whether mixing each pair of the following results in a buffer.
a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.
YES. NH₃ is a weak base and NH₄⁺ (from NH₄Cl ) is its conjugate base.
b. 50.0 mL of 0.10 M HCl with 35.0 mL of 0.150 M NaOH.
NO. HCl is a strong acid and NaOH is a strong base.
c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.
YES. HF is a weak acid and it reacts with NaOH to form NaF, which contains F⁻ (its conjugate base).
d. 175.0 mL of 0.10 M NH₃ with 150.0 mL of 0.12 M NaOH.
NO. Both are bases.
Answer:
The HCl will dissolve the calcium readily
Explanation:
HCl will react with d calcium, dissolving it to produce Hydrogen gas
Ionic compounds are formed by the bonding of non-metals to metals. Because inonic bonds involve electon transfer, the result is a mixture of ions; positive and negative, following the laws of electrostatics, like charges attract. These ions then form a giant structure (lattice) of ionic bonds and it is because of this that ionic compounds are solids (unless dissolved in water) and have extremely high melting and boling temparatures. In additions, beucase of the fixed placement of ions (charged particles) in a lattice, in the solid state ionic compounds don't conduct electricity very well but if dissolved in water (aqueous solution) the ions are free to move and carry a current.
