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2 years ago

What is the formula for tin(IV) sulfide? A. Sn4S B. SnS2 C. Sns D. SnS4

Chemistry

1 answer:

defon2 years ago

6 0

Answer:

$SnS_{2}$

Explanation:

The formula for tin(IV) sulfide is SnS $_{2}$

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The density of an unknown metal was determined to be 2.85 g/ml. the actual density was 2.70 g/ml. what is the percent error in t

Tasya [4]

% error = $\frac{|experimental - theoretical|}{theoretical}$ x 100%

Experimental: 2.85
Actual (theoretical): 2.70

% error = $\frac{2.85-2.70}{2.70}$ x 100% = .055555 x 100% = 5.56%

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3 years ago

Seasonal variation on earth is due to the

Iteru [2.4K]

The tilt of the Earth on its axis is what causes the seasons.

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3 years ago

Which of the following might a chemist choose to study?

Serjik [45]

Answer:

B. Better ways to recycle plastics

Explanation:

A chemist might choose to study better ways to recycle plastics because there may be certain types of chemicals that can disintegrate the plastic..

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2 years ago

Which of the following is a primary cause of LO/TO accidents?

Marianna [84]

<h2>Answer:</h2>

The correct answer is

A) Regular operation

<h2>Explanation:</h2>

Even those workplaces that have established LO/TO processes face challenges, including: Lack of specific procedures written for each piece of equipment identifying all energy sources and energy isolation devices. Lack of comprehensive safety training for everyone in the workplace. Incorrect tag use.

So, regular operation is the primary cause of LO/TO accidents.

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3 years ago

Read 2 more answers

1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant

vodomira [7]

The masses of the components are obtained as;

Sodium hydrogen carbonate = 3.51 g
Sodium carbonate = 8.708 g

<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

$2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)$

Now, the loss in mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g - 8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

Learn more about anhydrous sodium carbonate :brainly.com/question/20479996

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1 year ago