Answer:
12.33 cal/sec
Explanation:
As we know,
1 Kcal = 1000 cal
So,
0.74 Kcal = X cal
Solving for X,
X = (0.74 Kcal × 1000 cal) ÷ 1 Kcal
X = 740 cal
Also we know that,
1 Minute = 60 Seconds
Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,
= 740 cal / 60 sec
= 12.33 cal/sec
Answer:
Therefore, the oxidation state of sulphur atoms in Na2S2O3 is −2 and +6.
The mass of HNO3 obtained is 12.46 g from the given reaction.
The chemical reaction is :
Potassium Nitrate + Sulphuric acid ------> Potassium Bisulphate + Nitric acid.
The above reaction is basically used for the making of nitric acid.
Less than 200 degree celcius the Nitric acid if more than 200 degree celcius then it will form Potassium Sulphate.
Now,
1 mol of KNO3 reacts with1 mol of concentrated H2SO4 to give 1 mol HNO3
Molar Mass of KNO3 = 101.1 g
Molar mass of H2SO4 = 98.07 g
Mass of H2SO4 that can react with 20 g of KNO3 = (20 g* 98.07 g )/ 101.1 g
= 19.4 g
Molar mass of nitric acid= 63.01 g
Hence mass of nitric acid produced by 20 g of KNO3 = (20 g * 63.01 g ) / 101.1 g = 12.46 g
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To find the experimental value I believe we add up all the temperatures found by each trial and divide by the number of trials
When added up and divided up this is 50.7 C
Then we continue with accepted value minus experimental value over accepted
53.0 - 50.7 / 53.0 x 100
4.3% percent error
