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choli [55]
4 years ago
10

What would you multiply "moles of oxygen" by to get the units "grams of oxygen"?

Chemistry
1 answer:
lozanna [386]4 years ago
5 0
The atomic mass, which is the weight of the specific element. It’s also on the periodic table right below the element symbol. Atomic mass for oxygen would be 16.00
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Draw structures for the eight constitutional isomers with molecular formula c9h12 that contain a benzene ring.
kipiarov [429]
Following are the Nine Constitutional Isomers of Molecular formula C₉H₁₂. In the drawing of isomers the Benzene ring was kept intact. All isomers were drawn among the four carbons. Isomers are shown below,

8 0
3 years ago
For the reaction:
Zepler [3.9K]

Answer:

The equilibrium constant for CO now

= 0.212 M

For H₂O

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

Explanation:

The chemical equation for the reaction is:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

The ICE Table for this reaction can be represented as follows:

                   CO(g)      +   H2O(g)   ⇌    CO2(g)   +     H2(g)

Initial            0.5                0.5                   -                      -

Change        -x                   -x                      + x                + x

Equilibrium   0.5 -x           0.5 - x

The equilibrium constantK_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}

K_c = \dfrac{[x]^2}{[0.5-x]^2}

where; K_c = 1.845

1.845 = \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}^2

\sqrt{1.845}= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}

1.3583= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}

1.3583 (0.5-x) = x

0.67915  - 1.3583x = x

0.67915  = x +  1.3583x

0.67915 = 2.3583x

x = 0.67915/2.3583

x = 0.2880

The equilibrium constant for CO now = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For H₂O = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

3 0
3 years ago
"The pH of a solution of household ammonia, a 0.950-M solution of NH3, is 11.612. What is Kb" for NH3
aalyn [17]

Answer:

Kb = 1.77x10⁻⁵

Explanation:

When NH₃, a weak base, is in equilibrium with waterm the reaction that occurs is:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

And the dissociation constant, Kb, for this equilibrium is:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

To find Kb you need to find the concentration of each species. The equilibrium concentrations are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

<em>Where X is reaction coordinate.</em>

You can know [OH⁻] and, therefore, X, with pH of the solution, thus:

pH = -log [H⁺] = 11.612

[H⁺] = 2.4434x10⁻¹²

As 1x10⁻¹⁴ = [H⁺] [OH⁻]

1x10⁻¹⁴ / 2.4434x10⁻¹² = [OH⁻]

4.0926x10⁻³ = [OH⁻] = X

Replacing, concentrations of the species are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

[NH₃] = 0.9459M

[NH₄⁺] = 4.0926x10⁻³M

[OH⁻] = 4.0926x10⁻³M

Replacing in Kb expression:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Kb = [4.0926x10⁻³M] [4.0926x10⁻³M] / [0.9459M]

<h3>Kb = 1.77x10⁻⁵</h3>
7 0
3 years ago
When atoms combine, the force of attraction that holds them together is a(
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Electrostatic, meaning the attraction from one's positive nucleus is to the negative electrons of the other atom and vis versa.
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