Answer:
secondary alcohol
Explanation:
NaOH in solution provides OH- nucleophile.
When 2-chloropropane is treated with NaOH, nucleophillic substitution reaction takes place.Here leaving group is Chlorine atom (Cl).
Here OH- replaces Chlorine (Cl) to form 2-propanol which is a secondary alcohol.(OH group attached to 2° carbon)
Other possibility is elimination reaction in which NaOH acts as base.
NaOH acts as base when it is concentrated and aqueous NaOH acts as nucleophile.
In that case,the product formed will be an alkene.(not there in option)
Answer:
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Answer:
- <em><u>% of calcium carbonate = 28.8%</u></em>
Explanation:
The <em>percentage </em>of a substance in a mixture is calculated with the formula:
- % of substance = (mass of substance / mass of mixture) × 100
In this case we have:
- mass of substance = mass of <em>calcium carbonate</em> = 1.73 g
- mass of<em> mixture</em> = mass of <em>calcium carbonate</em> + mass of <em>sodium carbonate</em> + mass of <em>magnesium sulfate</em>
- mass of <em>mixture</em> = 1.73 g + 2.34 g + 1.93 g = 6.00 g
Now you can substitute the values in the formula for percentage:
- % of substance = (1.73g / 6.00g) × 100 = 28.8%