A neutral atom has the following electron configuration: What is the chemical symbol for the atom? How many electrons does the a
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Answer:
The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg
Explanation:
Heat gain by ice = Heat lost by water
Thus,
Heat of fusion +
Where, negative sign signifies heat loss
Or,
Heat of fusion +
Heat of fusion = 334 J/g
Heat of fusion of ice with mass x = 334x J/g
For ice:
Mass = x g
Initial temperature = 0 °C
Final temperature = 6 °C
Specific heat of ice = 1.996 J/g°C
For water:
Volume = 353 mL
Density of water = 1.0 g/mL
So, mass of water = 353 g
Initial temperature = 26 °C
Final temperature = 6 °C
Specific heat of water = 4.186 J/g°C
So,
345.976x = 29553.16
x = 85.4197 kg
Thus,
<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>
Answer:
Explanation:
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In this case, according to the chemical reaction:
H2 + 1/2 O2 --> H2O
Since both hydrogen and oxygen are the reactants and the rate laws are written in terms of the concentration of reactants and the rate constant, we obtain:
Whereas the negative sign represents the consumption of those reactants and the power 1/2 the stoichiometric coefficient of oxygen in the reaction.
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<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.
<u>Explanation:</u>
For the given chemical reaction:
The expression of for above reaction follows:
........(1)
We are given:
Putting values in above equation, we get:
To calculate the molarity of solution, we use the equation:
Moles of hydrogen gas = 0.30 mol
Volume of solution = 2.0 L
Putting values in above equation, we get:
When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.
Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M
Now, the equilibrium is shifting to the reactant side. The equation follows:
Initial: 0.1 0.1 0.4 0.1
At eqllm: 0.1+x 0.1+x 0.4-x 0.25-x
Putting values in expression 1, we get:
Neglecting the negative value of 'x'
Calculating the concentrations of the species:
Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M
Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M
Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M
Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M
Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.