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3 years ago

7

A neutral atom has the following electron configuration: What is the chemical symbol for the atom? How many electrons does the a

tom have? How many electrons are in the atom?

1 answer:

tiny-mole [99]3 years ago

3 0

Answer:

pls the image didn't come

Explanation:

ols the. atom's image didn't appear

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Im 99% sure that it is B

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3 years ago

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What statements are always true about limiting reactants?

alisha [4.7K]

Answer:

5.The limiting reactant is completely used up in the reaction

Explanation:

The limiting reactant is completely used up in the reaction is the correct answer because a limiting reactant is a reactant in chemical reaction that is completely consumed or used up in the chemical reaction. Limiting reactant when it is completely used up limits the amount of products that will be formed. The reaction will be halted or will stop when the limiting reactant is totally used up.

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3 years ago

Consider the reaction below: 3 h2(g) + n2(g) ? 2 nh3(g) if there are 6 mol of nitrogen (n2) and more than enough hydrogen (h2),

Alex73 [517]

1 mol N₂ - 2 mol NH₃
6 mol N₂ - x mol NH₃

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3 years ago

Were any paint chip cards missing from your set? How did you determine they were or were not missing? How would you describe the

zmey [24]

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3 years ago

What mass of this substance must evaporate to freeze 190 g of water initially at 17 ∘C? (The heat of fusion of water is 334 J/g;

Nikolay [14]

The question is incomplete, here is a complete question.

$\Delta H_{vap}$ of $CCl_2F_2$ is 289 J/g. What mass of this substance must evaporate in order to freeze 190 g of water initially at 17 degrees C? (heat of fusion of water is 334 J/g; specific heat of water is 4.18 J/g.K).

Answer : The mass of this substance evaporate to freeze must be, 258.2 grams.

Solution :

First we have to calculate the total heat absorbed.

$\text{Total heat absorbed}=[m\times c_{p,l}\times (T_{final}-T_{initial})]+m\times \Delta H_{fusion}$

where,

m = mass of water = 190 g

$c_{p,l}$ = specific heat of liquid water = $4.18J/g.K$

$\Delta H_{fusion}$ = enthalpy change for fusion of water = $334J/g$

$T_{final}$ = final temperature = $17^oC=273+17=290K$

$T_{initial}$ = initial temperature = $0^oC=273+0=273K$

Now put all the given values in the above expression, we get:

$\text{Total heat absorbed}=[190g\times 4.18J/g.K\times (290-273)K]+190g\times 334J/g$

$\text{Total heat absorbed}=76961.4J$

Now we have to calculate the mass of substance.

As, 298 J of heat are absorbed by 1 g of $CCl_2F_2$

So, 76961.4 J of heat are absorbed by $\frac{76961.4J}{298J}\times 1g=258.2g$ of $CCl_2F_2$

Therefore, the mass of this substance evaporate to freeze must be, 258.2 grams.

7 0

3 years ago