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Artyom0805 [142]
3 years ago
7

How could you calculate the elasticity of a collision if you know the approach velocity and separation velocity of the colliding

objects
Physics
1 answer:
marishachu [46]3 years ago
6 0

Answer: Based on your table, how could you calculate the elasticity of a collision if you know the approach velocity and separation velocity of the colliding objects? You can calculate the elasticity of a collision by dividing separation velocity by approach velocity (Equation: Vs/Va).

Explanation:

plz mark me branilest

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<h3>What is Planck time?</h3>

The Planck time is approximately<u> 10^-44 seconds</u>. The smallest time interval, or "zeptosecond," that has so far been measured is <u>10^-21 seconds</u>. A photon traveling at the speed of light would need one Planck time <u>to traverse a distance of one </u><u>Planck length</u>.

<h3>What is Planck length?</h3>

Planck units are a set of measuring units used only in particle physics and physical cosmology. They are defined in terms of <u>four universal </u><u>physical constants</u> in such a way that when expressed in terms of these units, these physical constants have the numerical value 1. These units are a system of natural units because its definition is <u>based on characteristics of nature</u>, more especially the characteristics of free space, rather than a selection of prototype object, as was the case with Max Planck's original 1899 proposal. They are pertinent to the study of unifying theories like quantum gravity.

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2 years ago
True or False an overtone occurs when two or more sound waves are produced at the same time.
Setler79 [48]

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If an electron is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the elect
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Using Fleming’s left hand rule,

The magnetic force on the electron will be west. Example: If it is dropped above the equator in Africa, the electron will head towards North America.
4 0
3 years ago
A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o
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To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

\delta = \frac{PL}{AE}

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

P = 68*10^3 N

E = 200GPa  

A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2

Replacing we have,

\delta = \frac{PL}{AE}

\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}

\delta = 0.001932m

\delta = 1.93mm

Therefore the change in length is 1.93mm

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3 years ago
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