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cestrela7 [59]
3 years ago
9

Two point charges of equal magnitude (and opposite sign) are 7.5 cm apart. At the midpoint of the line connecting them, their co

mbined electric field has a magnitude of 45 N/C. What is the magnitude of each charge?
Physics
1 answer:
Shkiper50 [21]3 years ago
7 0

Comment

The only reason you can do this is that the charges are the same. If they were not, the problem would not be possible.

Equation

The field equation is, in its simplest form,

E = kq/r^2

So each of the charges are pulling / pushing in the same direction. The equation becomes.

kq/r^2 - (-kq/r^2) = Field magnitude in N/C

Givens

  • K = 9 * 10^9 N m^2 / c^2
  • E = 45 N/C
  • r = 7.5/2 = 3.75 cm * ( 1 m / 100 cm) = 0.0375 m
  • Find Q

Solution

k*q/0.0375 ^2 - (-kq/0.0375^2) = 45 N/C           Combine

2*k*q / 0.0375^2 = 45 N/C                                  Divide by 2

kq /(0.0375^2) = 22.5 N/C                                   Multiply by 0.0375^2

kq = 22.5 * 0.0375 ^2                                           Find d^2

kq = 22.5 * 0.001406                                            Combine

kq = 0.03164 N/C * m^2                                        Divide by k

q = 0.03164 N * m^2 /C / 9*10^9 N m^2 / c^2

q = 2.84760 * 10 ^8 C

I've left the cancellation of the units for you. Notice that only 1 C is left and it is in the numerator as it should be.


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6 0
3 years ago
How long have advances in astronomy been occurring? Only for the past few years
solniwko [45]

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3 0
3 years ago
On a distant planet, a rock falls in 48.4 s from the top of a 1.10e+02 m cliff to the planet surface below. What is the accelera
pav-90 [236]

this can be solve using the formala of free fall

t = sqrt( 2y/ g)

where t is the time of fall

y is the height

g is the acceleration due to gravity

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G = 0.0930 m/s2

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8 0
3 years ago
What is the energy stored between 2 Carbon nuclei that are 1.00 nm apart from each other? HINT: Carbon nuclei have 6 protons and
Andrei [34K]

Answer:

A. 8.29\times 10^{-18}\ J

Explanation:

Given that:

p = magnitude of charge on a proton = 1.6\times 10^{-19}\ C

k = Boltzmann constant = 9\times 10^{9}\ Nm^2/C^2

r = distance between the two carbon nuclei = 1.00 nm = 1.00\times 10^{-9}\ m

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

U = \dfrac{kQq}{r}

So, the potential energy between the two nuclei of carbon is as below:

U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J

Hence, the energy stored between two nuclei of carbon is 8.29\times 10^{-18}\ J.

8 0
3 years ago
The space shuttle is accelerated off its launch pad to a velocity of 525 m/s in 18.0 seconds.
Eva8 [605]

Answer: 29.17m/s^2

Explanation:

Given the following :

Velocity = 525 m/s

Time = 18 seconds

Acceleration = change in Velocity with time

Using the motion equation:

v = u + at

Where v = final Velocity

u = Initial Velocity and t = time

Plugging our values

525 = 0 + a × 18

525 = 18(a)

a = 525 / 18

a = 29.166666

a = 29.17 m/s^2

8 0
3 years ago
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