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emmasim [6.3K]
3 years ago
15

The formation of chemical bonds from separated atoms 1. is never spontaneous. 2. increases entropy. 3. is always endothermic. 4.

is always exothermic. 5. may be either endothermic or exothermic.
Chemistry
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

is always exothermic

Explanation:

You see, whether a process is endothermic or exothermic depends on the result of the operation; ΔHreaction= ΔHproducts - ΔHreactants.

If the enthalpy of reactants exceeds that of the products, then the process is exothermic.

We should remember that the energy of isolated atoms is always higher than the energy of the compound formed when the atoms bond together. Hence bond making is an exothermic process.

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Write the balanced net reaction for the following half cells: <br> Sn2+ / Sn<br> Cr2+ / Cr
GuDViN [60]

The balanced net reactiion for the following half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

<h3>What are Half cells ?</h3>

A half cell is one of the two electrodes of an electrochemical cell.

An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.

A salt bridge or direct contact is needed to connect two half cells.

The balanced net reactiion for the given half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

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2 years ago
Which of the following is a correct statement about collision theory?
rjkz [21]
The answer is D. Effective collisions lead to chemical reactions!
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3 years ago
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5 0
3 years ago
A solution of potassium hydroxide reacts completely with a solution of nitric acid. What solid mixture does it create?
KIM [24]

Answer:

\boxed{\text{KNO}_{3}}

Explanation:

The reaction is

KOH(aq) + HNO₃(aq) ⟶ KNO₃(aq) + H₂O(ℓ)

If you evaporate the water, the solid substance is the compound, potassium nitrate.

\boxed{\textbf{KNO}_{3}}

KNO₃(aq) ⟶ KNO₃(s)

4 0
3 years ago
Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).
faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 =  378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 =   0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

8 0
3 years ago
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