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erastovalidia [21]
2 years ago
8

Weight=1500n area=0.5 m2 pressure=​

Physics
1 answer:
Dmitriy789 [7]2 years ago
8 0

Answer: 6000N/m^2

Explanation:

Weight =1500N

Area =0.5m^2

Pressure =1500/(0.5^2)

               =6000N/m^2

Note: Newton is denoted by 'N' (Capital) and use '^' for powers.

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*How much energy is<br>transferred in lifting a 5 kg<br>Mass 3m​
AlexFokin [52]

Answer:

147 J

Explanation:

The energy transferred to potential energy is :

U = m * g * h = (5 kg) * (9.8 m/s^2) * (3 m) = 147 J

3 0
3 years ago
Rosalind is an impulsive child who seldom waits for her turn when playing with other children. Rosalind's father is also an impu
wariber [46]

Answer:

Alburt Bandura

Explanation:

Rosalind has learned to be impulsive and seldom waits for her turn when playing with other children, this trait she has learned  from her father, who is also an impulsive man.

The theorist who would most likely suggest that Rosalind has learned to be impulsive from watching her father is Alburt Bandura. Alburt in his famous Bebo Doll experiment confirmed that children learn from the adults behavior in their life.

3 0
3 years ago
Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis
WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

Where:

F is the gravitational force between Earth and Moon

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant  

M=5.972(10)^{24} kg is the mass of the Earth

m=7.349(10)^{22} kg is the mass of the Moon

r=3.9(10)^{8} m is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to F:

F=m.a_{C} (2)

Where a_{C} is the centripetal acceleration given by:

a_{C}=\frac{V^{2}}{r} (3)  

Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

\frac{V^{2}}{r}=G\frac{M}{r^{2}} (6)  

Finding V:

V=\sqrt{\frac{GM}{r}} (7)

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}} (8)

Finally:

V=1010.92 m/s

5 0
3 years ago
The caste system in India is illegal. True or False
anzhelika [568]
<span>Discrimination is illegal, but caste system is legal.
So answer: False</span>
4 0
3 years ago
Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 6.5 cm from the center of the bul
Deffense [45]

..........................................................

8 0
3 years ago
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