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FinnZ [79.3K]
3 years ago
6

Explain how you can determine the direction of a magnetic field produced by a wire if you know the diection of the current throu

h the wire.

Physics
2 answers:
Anarel [89]3 years ago
8 0
The fundamental rule of thumb that can be used to determine the direction of the magnetic field is the right hand rule. If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.
ololo11 [35]3 years ago
5 0

Explanation:

Right hand thumb rule : Point the thumb of your right hand in the direction of the current flow, the direction of curvature of the fingers will give us the direction of the magnetic field produced by current carrying wire. This rule was given by Maxwell.

1) If the current is moving in upward direction , the direction of the magnetic field will be in anti clock wise direction.

2) If the current is moving in downward direction , the direction of the magnetic field will be in clock wise direction.

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What is the effect on the gas’ pressure when compressing a gas to 1/3 of its volume? Explain
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Explanation:

It's pressure become three times larger because according to Boyles Law the pressure of fixed mass of gas is inversely proportional to it's volume provided that temp remains constant. That means a reduction in volume, will result in an increase in pressure and vice versa.

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3 years ago
Which of the following correctly describes the state of matter of one of the samples?
zheka24 [161]
I think the answer is D
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3 years ago
A car starts from rest and accelerates uniformly to a speed of 72km/hr over a distance of 500m. Find the acceleration of the car
Rom4ik [11]

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itsgoing to be aroud 36 speed

Explanation:

bc if u think about it it make sence

6 0
2 years ago
Can a 12 inch rubber band fit a 22 pound rubber band ball
Vlada [557]

Answer:

if it is a thiner one, yes it will fit because they can expand a pretty far distance

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4 0
2 years ago
A uniformly charged, thin ring has radius 15.0 cm and total charge +24.0 nC. An electron is placed on the ring’s axis a distance
djyliett [7]

Answer:

A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.

B. Veloctiy (Vb) = 1.66m/s

Explanation:

Given the following data

x(a) = 0.3m

x(b) = 0

q = 1.6×10^-19

Q = 24nc

r = 0.15m

Required: the motion of the electron and the velocity (Vb)

1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B

2. Potential energy and kinetic energy are given by

U(a) + K(a) = U(b) + K(b). . .1

Initial P.E and K.E are given as

U(a) = kQ/√x²(a) + a2

By substitution, we have

U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)

U(a) = -1.03×10^-16

Final P.E and K.E are given as

U(b) = KQ/√x²(b) + a2

By substitution, we have

U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²

U(b) = -2.3×10^16

3. By substitution into equation 1 becomes

-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2

V(b) = √2×1.27×10^-16/9.1×10^31

V(b) = 1.66×10^7m/s

4 0
4 years ago
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