Answer:
  F = 0.111015 N
Explanation:
For this exercise the force is given by Coulomb's law
         F = k q₁q₂ / r₂₁²
we calculate the electric force of the other two particles on the charge q1
Charges q₁ and q₂
the distance between them is
           r₁₂ = y₁ -y₂
           r₁₂ = 0.30 + 0.30
           r₁₂ = 0.60 m
let's calculate
           F₁₂ = 9 10⁹ 2 10⁻⁶ 2 10⁻⁶ / 0.60 2
           F₁₂ = 1 10⁻¹ N 
directed towards the positive side of the y-axis
Charges 1 and 3
Let's find the distance using the Pythagorean Theorem
              r₁₃ = RA [(0.40-0) 2 + (0-0.30) 2]
              r₁₃ = 0.50 m
             F₁₃ = 9 10⁹ 2 10⁻⁶ 4 10⁻⁶ / 0.50²
             F₁₃ = 1.697 10⁻² N
The direction of this force is on the line that joins the two charges (1 and 3), let's use trigonometry to find the components of this force
            tan θ = y / x
            θ = tan⁻¹ y / x
           θ = tan⁻¹ 0.3 / 0.4
            tea = 36.87º
     The angle from the positive side of the x-axis is
          θ ’= 180 - θ
         θ ’= 180 - 36.87
         θ ’= 143.13º
        sin143.13 = F_13y / F₁₃
            F_13y = F₁₃ sin 143.13
            F{13y} = 1.697 10⁻² sin 143.13
            F_13y = 1.0183 10⁻² N
             cos 143.13 = F_13x / F₁₃
            F₁₃ₓ = F₁₃ cos 143.13
            F₁₃ₓ = 1.697 10⁻² cos 143.13
            F₁₃ₓ = -1.357 10-2 N
Now we can find the components of the resultant force
           Fx = F13x + F12x
           Fx = -1,357 10-2 +0
           Fx = -1.357 10-2 N
           Fy = F13y + F12y
          Fy = 1.0183 10-2 + 1 10-1
           Fy = 0.110183 N
We use the Pythagorean theorem to find the modulus
          F = Ra (Fx2 + Fy2)
          F = RA [(1.357 10-2) 2 + 0.110183 2]
          F = 0.111015 N
Let's use trigonometry for the angles
          tan tea = Fy / Fx
           tea = tan-1 (0.110183 / -0.01357)
           tea = 1,448 rad
to find the angle about the positive side of the + x axis
            tea '= pi - 1,448
            Tea = 1.6936 rad