5. 54 J of heat is required to raise the temperature of a 2.47g unknown substance from 17.10C to 46.70C. a) Calculate the specif
ic heat of the substance b) What is the substance?
1 answer:
<h3>upemnavsi wiwnownivv</h3>
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v = 75 mph = 33.52 m/s
u = 55 mph = 24.58 m/s
t = 4 sec
acceleration = v-u/t
= 33.52-24.58/4
= 8.94/4
= 2.235 m/s
Answer: 19.4 g/cm3
Explanation: density is the relationship between mass over volume.
So density of gold is 15.7g/0.81cm3 = 19.4 g/cm3
Answer:
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