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dimaraw [331]
3 years ago
14

5. 54 J of heat is required to raise the temperature of a 2.47g unknown substance from 17.10C to 46.70C. a) Calculate the specif

ic heat of the substance b) What is the substance?
Chemistry
1 answer:
musickatia [10]3 years ago
5 0
<h3>upemnavsi wiwnownivv</h3>
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How many moles of argon are in 13.9 g of argon?
OLEGan [10]

Answer:

0.348 moles Ar

Explanation:

You can determine the moles of argon (Ar) by multiplying the given mass by the atomic mass of argon. This number gives the mass in grams per 1 mole. It is important to arrange the conversion in a way that allows for the cancellation of units. The final answer should have 3 significant figures to match the sig figs of the given value (13.9 = 3 sig figs).

Atomic Mass (Ar): 39.948 g/mol

 13.9 g Ar              1 mole
-----------------  x  ------------------  =  0.348 moles Ar
                            39.948 g

3 0
2 years ago
What is meant by the half-life of a radioactive substance
Shtirlitz [24]

Answer:

Explanation:

The half life of a radioactive atom is the time taken for half of the radioactive nuclei to disintegrate. The shorter the half life, the faster a radioactive nuclei decays.

Half life is often expressed as:

                               Half life = \frac{0.693}{λ}

Where λ is the decay constant.

3 0
3 years ago
Mechanical waves are classified according to
Natasha_Volkova [10]

mechanical waves are classified by how they move. there are two types of mechanical waves:transverse waves and longitudinal waves.

4 0
3 years ago
Given the balanced ionic equation:
bezimeni [28]

Answer : The correct option is, (4) 6.0 mol

Explanation :

The given balanced chemical equation is,

3Pb^{2+}+2Cr\rightarrow 3Pb+2Cr^{3+}

In this reaction, lead undergoes reduction and chromium undergoes oxidation.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

Half reactions of oxidation-reduction are :

Oxidation : 2Cr\rightarrow 2Cr^{3+}+6e^-

Reduction : 3Pb^{2+}+6e^-\rightarrow 3Pb

From the reduction reaction, we conclude that 6 moles of electrons gained by the 3 moles of lead ions.

Hence, the correct option is, (4) 6.0 mole

5 0
3 years ago
What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = −4600 J/mol. Answer in units of J/K.
Ira Lisetskai [31]

Answer:

-1.71 J/K

Explanation:

To solve this problem we use the formula

ΔS = n*ΔH/T

Where n is mol, ΔH is enthalpy and T is temperature.

ΔH and T are already given by the problem, so now we calculate n:

Molar Mass C₂H₅OH = 46 g/mol

2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol

Now we calculate ΔS:

ΔS = 0.0589 mol * −4600 J/mol / 158.7 K

ΔS = -1.71 J/K

4 0
3 years ago
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