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Neko [114]
3 years ago
14

PLEASE HURRRYYYY

Chemistry
1 answer:
stealth61 [152]3 years ago
3 0

Answer:

HCO₂H

Explanation:

A buffer is defined as the mixture between a weak acid and its conjugate base, or vice versa, in an aqueous solution.

The HCO₂Na (Sodium formate), is the conjugate base of formic acid, HCO₂H, a weak acid of pKa = 3.75.

Thus, to make a buffer using HCO₂Na, the other substance the buffer should contain is <em>HCO₂H</em>

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How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?
Katen [24]
The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J
3 0
3 years ago
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N2H4+H2O2 ——&gt; N2+H2O coefficient
const2013 [10]

Answer:

N2H4 + 2H2O2 ---->N2 + 4H2O

Explanation:

N=2            N=2

H=6 ->8      H=2 ->8

O=2 -> 4     O=1 -> 4

Add coefficients to hydrogen peroxide on the left and water on the right, so that there is an equal number of hydrogens and oxygens.

3 0
3 years ago
Which laws can be combined to form the ideal gas law?
ahrayia [7]
Answer: Charles's law, Avogadro's law andd Boyle's law.

Charles law states the constant ratio of volume to temperature, at constant pressure. Boyle's law states the constat product of pressure and volumen at constant temperature. Avogadro's law states that equal volumes of gases at the same temperature and pressure have equal number of particles.

So, all those three laws combined state the relation of pressure, volume, temperature and number of particles of a gas, which is what the ideal gas law does: PV = n RT.
4 0
3 years ago
Read 2 more answers
Calculate the poh of this solution. round to the nearest hundredth. ph = 1.90 poh =
Viktor [21]

Answer:

The answer is 5.10

Explanation:

<h3><u>Given</u>;</h3>
  • pH = 1.9
<h3><u>To </u><u>Find</u>;</h3>
  • pOH = ?

We know that

pH + pOH = 7

pOH = 7 – pH

pOH = 7 – 1.90

pOH = 5.10

Thus, The pOH of the solution is 5.10

6 0
2 years ago
1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
Andrej [43]

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

Mg+2HCl\rightarrow MgCl_2+H_2

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

n_{H_2}^{by\  HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl}  =0.0284molH_2\\\\n_{H_2}^{by\  Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg}  =0.690gMg

Thus, the mass of excess magnesium turns out:

m_{Mg}^{excess}=2.38g-0.690g=1.69gMg

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%

Best regards!

8 0
3 years ago
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