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Masteriza [31]
2 years ago
8

The track along which electricity flows is called a: fuse circuit switch

Chemistry
1 answer:
Pavel [41]2 years ago
4 0
It is called a circuit.
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I think it will carbon hope it helps

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What is force? Why?​
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You know that a circuit is a path along which electrical charges can flow. In this activity, you are going
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2 years ago
A sample of a compound contains 32.0 g C and 8.0 g H. Its molar mass is 30.0 g/mol. What is the compound’s molecular formula
Grace [21]
The compound's molecular formula is C2H6. This is obtained by:
  
            mass             moles               divided by smallest moles
C          32g         32/12 = 2.67                                 1
H           8g           8/1.01 = 7.92                        approx. 3

Next, divide both terms by the smallest number of moles, 2.67. This gives 1 and 3. So the empirical formula is CH3 which has a molar mass of 15g/mol. Given the molar mass of the molecular formula as 30g/mole, we can calculate the factor by which to multiply the subscripts of CH3.

X = molar mass of molecular formula / molar mass of empirical formula = 30/15
X=2

So (CH3)2 is C2H6.
3 0
2 years ago
If you have 150 grams of s8, how many moles of so2 can you make?
ruslelena [56]

Answer : You can make 4.68 moles of SO₂

Explanation:

Step 1 : Write balanced equation.

S₈ can combine with oxygen to form SO₂ gas. The balanced equation for this reaction is written below.

S_{8}  + 8 O_{2} \rightarrow 8 SO_{2}

Step 2 : Find moles of S₈

The formula to calculate mol is

mole = \frac{grams}{MolarMass}

Molar mass of S₈ is 256.5 g/mol

mole = \frac{150grams}{256.5 g/mol}

mole = 0.585 mol

we have 0.585 mol of S₈

Step 3: Use mole ratio to find moles of SO₂

The mole ratio of S₈ and SO₂ can be found using balanced equation which is 1:8

That means 1 mol of S₈ can form 8 moles of SO₂.

Let us use this as a conversion factor to find moles of SO₂

0.585 mol (S_{8}) \times \frac{8 mol (SO_{2})}{1 mol (S_{8})}  = 4.68 mol

Therefore we have 4.68 moles of SO₂

4 0
3 years ago
Read 2 more answers
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