Can u help me with this it's hard
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Integration will be ln | ( x /9 ) + ( ) | + c .
Given ∫ 1 dx / ( - 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / ( - 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + ( / 9 ) | + c
= ln | ( x /9 ) + ( ) | + c
Hence , the integration will be ln | ( x /9 ) + ( ) | + c .
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The hypotenuse of the triangle is given by:
Substituting values:
Clearing CB we have:
Then, the perimeter of the triangle is:
Substituting values:
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5
Substituting values:
Clearing CB we have:
Then, the perimeter of the triangle is:
Substituting values:
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5