Answer:
Step-by-step explanation:
Let's label this triangle as triangle ABC. Side AB is 18, side BC is 20 and side CA is 25 and the angle we are looking for is angle C. Use the Law of Cosines to find the missing angle. You have to use the Law of Cosines because in order to use the Law of Sines you have to have an angle given and we don't so we have no other options. In our case,
which for us looks like this:
and
and
and
and
Use the 2nd button and the cos button to find the missing angle.
Angle C = 45.4 which is, rounded to the nearest degree, 45°
Answer:
60m²
Step-by-step explanation:
my dude you need to know this. A=bh. A=10(6).
15
(even if it’s a joke I want points)
Draw an equilateral triangle with side lengths of 1. Each angle here is 60 degrees, which is true of any equilateral triangle.
Now draw another equilateral triangle that has side lengths of 2 units. Clearly this triangle is not the same size as the previous one, but the angles are all still 60 degrees.
We have an example in which there are 2 triangles with the same angles, but the triangles are not congruent. Therefore, having info about congruent angles only isn't sufficient to prove triangles to be congruent.
First, we need to find the GCF (greatest common factor) of each of the number.
1. List out the prime factors of each of them.
2. Multiply the prime factors that the two numbers have in common
60 = 2 × 2 × 3 × 5
84 = 2 × 2 × 3 × 7
The common factors are: 2 and 3
GCF = 2 × 2 ×3
GCF = 12
Factor out 12 from the equation
12(5x - 7)
