Which element is correctly classified

Since both HBr and KOH are strong, we expect these reactions to occur fully. You mix 2 moles of HBr with 3 moles of KOH in enoug

AysviL [449]

Answer: pH = 14

Explanation: Please see the attachments below

8 0

3 years ago

Will you obtain a pure solid in evaporation technique? Justify your answer

aniked [119]

Evaporation technique is used to separate a compound dissolved in a solvent by vaporizing the solvent and converting it to gaseous state. This leaves behind the solid residue present in the solution after the pure solvent is vaporized. The solvent vapors can be collected and condensed to get pure solvent. But the solid residue cannot be considered pure as it is the left over solid after all the solvent is evaporated. If the solution has some impurities, the solid left over includes all of the impurities. So, we cannot obtain a pure solid in evaporation technique.

3 0

3 years ago

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

irina1246 [14]

Answer:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Explanation:

Step 1: Write the unbalanced chemical equation,

C₄H₁₀ + O₂ → CO₂ + H₂O

Step 2: Balance Carbon Atoms;

As there are 4 carbon atoms on left hand side and 1 carbon atoms on right hand site therefore, to balance them multiply CO₂ on right hand side by 4 i.e.

C₄H₁₀ + O₂ → 4 CO₂ + H₂O

Step 3: Balance Hydrogen Atoms;

There are 10 hydrogen atoms on left hand side and 2 hydrogen atom on right hand site therefore, to balance them multiply H₂O on left hand side by 5 i.e.

C₄H₁₀ + O₂ → 4 CO₂ + 5 H₂O

Step 4: Balance Oxygen Atoms:

Now there are 2 oxygen atoms in reactant side and 13 in product side. So, multiply O₂ by 6.5 i.e.

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

Step 5: Remove fraction coefficients as,

Multiply whole equation by 2 to get rid of fractions i.e.

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

7 0

2 years ago

What are two things required for something to be matter?

almond37 [142]

Atoms and particles

6 0

3 years ago

Read 2 more answers

A gas within a piston–cylinder assembly undergoes an isothermal process at 400 K during which the change in entropy is −0.3 kJ/K

Karolina [17]

Answer:

W = -120 KJ

Explanation:

Since the piston–cylinder assembly undergoes an isothermal process, then the temperature is constant.

Thus; T1 = T2 = 400K

change in entropy; ΔS = −0.3 kJ/K

Formula for change in entropy is written as;

ΔS = Q/T

Where Q is amount of heat transferred.

Thus;

Q = ΔS × T

Q = -0.3 × 400

Q = -120 KJ

From the first law of thermodynamics, we can find the workdone from;

Q = ΔU + W

Where;

ΔU is Change in the internal energy

W = Work done

Now, since it's an ideal gas model, the change in internal energy is expressed as;

ΔU = m•C_v•ΔT

Where;

m is mass

C_v is heat capacity at constant volume

ΔT is change in temperature

Now, since it's an isothermal process where temperature is constant, then;

ΔT = T2 - T1 = 0

Thus;

ΔU = m•C_v•ΔT = 0

ΔU = 0

From earlier;

Q = ΔU + W

Thus;

-120 = 0+ W

W = -120 KJ

8 0

3 years ago