We have that the the density of FeS is mathematically given as
From the question we are told
Iron(II) sulfide has a primitive <em>cubic</em> unit cell with <em>sulfide</em> ions at the <em>lattice points.</em>
The ionic radii of iron(II) ions and sulfide ions are 88 pm and 184 pm, respectively.
What is the density of FeS (in g/cm3)?
<h3>
Density</h3>
Generally the equation for the Velocity is mathematically given as
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The cell proliferates to produce many cells that result in multicellar organism.
answer
<h3>
Answer:</h3>
1.827 × 10²⁴ molecules H₂S
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Compounds</u>
- Writing Compounds
- Acids/Bases
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
103.4 g H₂S (Sulfuric Acid)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
1.82656 × 10²⁴ molecules H₂S ≈ 1.827 × 10²⁴ molecules H₂S
A mixture in which composition is constant throughout the mixture is said to be homogeneous mixture.
Now, oil and vinegar dressing is not considered as a homogeneous mixture because composition is not uniform.
Concrete is made up of three components. Thus, composition is not uniform, so it is not a homogeneous mixture.
A mixture of salt and pepper, when salt is mixed in pepper then the mixture is not uniform as white flecks of salt and black flecks of pepper can be seen in the mixture. Thus, it is not a homogeneous mixture.
Salt water is uniform mixture. Thus, it is a homogeneous mixture.
Thus, salt water is the correct answer.
Answer:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Explanation:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Magnesium is more electro positive than aluminum hence it functions as the anode. Six electrons are lost/gained in the redox process as shown in the oxidation and reduction half reaction equations above. Magnesium is oxidized to magnesium ion while aluminum is reduced to elemental aluminum.
