(a) The initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.
(b) The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.
<h3>
Initial vertical velocity</h3>
The initial vertical velocity of the stone is calculated as follows;
Vi = Vsinθ
Vi = 22 x sin(50)
Vi = 16.85 m/s
<h3>Initial horizontal velocity</h3>
Vxi = V cosθ
Vxi = 22 x cos(50)
Vxi = 14.14 m/s
<h3>Final vertical velocity of the stone</h3>
Vf = Vi - gt
where;
- Vf is the final vertical velocity = 0 at maximum height
<h3 /><h3>Final horizontal velocity of the stone</h3>
Vfx = Vxi = 14.14 m/s
Thus, the initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.
The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.
Learn more about vertical velocity here: brainly.com/question/24949996
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Use this formula where:
∝ is the average distance between the centers of the two bodies
G is the gravitational constant
M1 and M2 are masses of the parent body and the orbiting body respectively.
Answer:
135degrees
Explanation:
Given that a vector starts at the point (0.0) and ends at (3,-3)
y component value = -3
x component value = 3
angle of the displacement theta = arctan(y/x)
theta = arctan(-3/3)
theta = arctan (-1)
theta = -45degrees
Since tan is negative in the second quadrant
theta = 180 - 45
theta = 135degrees
Hence the angle of the displacement is 135degrees
Answer:
T = 0.71 seconds
Explanation:
Given data:
mass m = 1Kg, spring constant K = 78 N/m, time period of oscillation T = 0.71 seconds.
We have to calculate time period when this same spring-mass system oscillates vertically.
As we know

This relation of time period is true under every orientation of the spring-mass system, whether horizontal, vertical, angled or inclined. Therefore, time period of the same spring-mass system oscillating vertically too remains the same.
Therefore, T = 0.71 seconds
Answer:
Part b)
h = 78.5 m
Part c)
v = 39.24 m/s
Explanation:
Part b)
If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval
here if ball start from rest
then its displacement is given as



Part c)
Speed of the bearing at the end of the motion of the ball


