Why is this website not work how i want it this is so annoying

Physics

2 answers:

hram777 [196]3 years ago

8 0

I know right!!!!!! Like frr so annoying

Mice21 [21]3 years ago

5 0

It depends how you want it to work do you want to take a picture oh yea and to do that you must create a account btw

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A force of 1 N is the only horizontal force exerted on a block, and the horizontal acceleration of the block is

SVEN [57.7K]

The mass of the first block will be three times the mass of the second block.

According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;

$F\ \alpha \ a$

$F = ma$

F is the acting force

m is the mass

a is the acceleration of the body

Given the following parameters

Constant force F = 1N

For the first block with the acceleration of "a"

1 = m₁a

a = m₁/1

m₁ = a .................1

For the second block, acceleration is thrice that of the first. This means;

F = m(3a)

1 = 3ma

$m_2=\frac{1}{3a}$ ..........................2

Divide both equations

$\frac{m_1}{m_2} =\frac{a}{(\frac{1}{3a} )}\\\frac{m_1}{m_2} = 3\\m_1 = 3m_2$

From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.

Learn more here: brainly.com/question/19030143

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3 years ago

Three samples of gas each exert 740. mm Hg in separate 2 L containers. What pressure do they exert if they are all placed in a s

Usimov [2.4K]

According to Dalton's law of partial pressure, the total pressure exerted is simply equal to the sum of the partial pressures of the individual gases. Given that all three samples of gas each exert 740 mmHg, when they are placed in a single 2 L container, they exert a pressure of 2220 mmHg on the container which is the sum of their individual pressures.

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4 years ago

If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N , what is the normal

Eddi Din [679]

Answer:

So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.

Now,

We have F=ma,

and a=v/t,

so we can have another equation for it as,

Now, providing the required data to, it; ∴t =2 sec,

F=(1)×(20/2),