Explanation:
Seismic refraction is the bending of the seismic waves as they pass geological layers of the earth due to different densities. This is especially true for Primary waves because they can pass through all the layers of the earth both liquid and solid.
Seismic reflectivity is the bouncing back of seismic waves at a boundary of geological layers due to different densities or subsurface formation. This is especially true for secondary waves that are unable to pass through liquid layers of the earth like the outer core and mantle. When they reach the boundary of these layers they bounce back towards the earth's surface.
These properties of P and S waves are used to ‘auscultate’ the epicenter of an earthquake by triangulation.
Learn More:
For more on Seismic Reflection and Seismic Refraction check out;
brainly.com/question/13502364
#LearnWithBrainly
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
A infared light has a higher
Answer:
The wavelength is 4.55 m.
Explanation:
Given data
- Frequency (ν): 66.0 MHz = 66.0 × 10⁶ Hz = 66.0 × 10⁶ s⁻¹
- Speed of light (c): 3.00 × 10⁸ m/s
- Wavelength (λ): To be found
We can determine the wavelength of the radio waves using the following expression.
c = λ × ν
λ = c / ν
λ = (3.00 × 10⁸ m/s)/66.0 × 10⁶ s⁻¹
λ = 4.55 m
