Answer:
Mol. mass of ethyl alcohol =C2H5OH=46
No. of moles of ethyl alcohol =4660=1.304
Mol. mass of methyl alcohol =CH3OH=32
No. of moles of methyl alcohol =3240=1.25
′XA′, mole fraction of ethyl alcohol =1.304+1.251.304=0.5107
′XB′, mole fraction of methyl alcohol =1.304+1.251.25=0.4893
Partial pressure ethyl alcohol =XAp˙A0=0.5107×44.5=22.73mmHg
Partial pressure methyl alcohol =XBp˙B0=0.4893×88.7=73.40mmHg
Total vapour pressure of solution =22.73+43.40=66.13mmHg
Mole fraction of methyl alcohol in the vapour
=Total vapour pressurePartial pressure of CH3OH
Explanation:
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