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3 years ago

Four and sixty eight thousandths in decimal form

Mathematics

2 answers:

kumpel [21]3 years ago

3 0

Answer:4.068

Step-by-step explanation:

BigorU [14]3 years ago

3 0

Answer:

4.068

Step-by-step explanation:

( i think. I haven't done decimals in a while)

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Help please I need this today

Katen [24]

Triangles a are similar because they have the same degrees

And Triangles d are similar because they are the same shape

3 0

3 years ago

Midpoint anyone

Natali [406]

Answer:

The answer is S(1,8)

Step-by-step explanation:

4 0

3 years ago

The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.

Pavlova-9 [17]

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

4 0

2 years ago

Which of the following sets of lengths can Sean use to make a right triangle?

Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

$c^2=a^2+b^2$

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

Verify each case

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

$18^2=5^2+15^2$

$324=250$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

$16^2=8^2+12^2$

$256=208$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

$15^2=5^2+13^2$

$225=194$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

$17^2=8^2+15^2$

$289=289$ ----> is true

therefore

Sean can make a right triangle with this set of lengths

6 0

2 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago