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Naddika [18.5K]
3 years ago
15

Study the graphs below what type of trend and pattern in observed .

Engineering
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

negative and linear

Explanation:

its a straight line going down

Scrat [10]3 years ago
4 0
It’s a negative as it’s going down
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A nanometer connected to a pipe indicates a negative gauge pressure of 70mm of mercury .what is the pressure in the pipe in N/m^
prohojiy [21]

Based on the calculations, the absolute pressure in the pipe is equal to 90,670.4‬ N/m².

<h3>How to calculate the absolute pressure?</h3>

Mathematically, absolute pressure can be calculated by using this formula:

P_{abs} = P_{atm} + P_{guage}

<u>Scientific data:</u>

Atmospheric pressure (Patm) = 1 bar = 1 × 10⁵ N/m²

Head (h) = -70mmhg = -0.07 m hg

Acceleration due to gravity = 9.8 m/s²

Density of mercury = 13,600 kg/m³.

Next, we would determine the gauge pressure:

P_{guage} = \rho gh\\\\P_{guage} =  -13600 \times 9.8 \times 0.07\\\\P_{guage} = -9,329.6\;N/m^2

Now, we can calculate the absolute pressure:

P_{abs} = P_{atm} + P_{guage}\\\\P_{abs} = 1 \times 10^5 - 9329.6

Absolute pressure = ‭90,670.4‬ N/m².

Read more on absolute pressure here: brainly.com/question/10013312

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6 0
2 years ago
A powerful contribution of the 1st and 2nd laws is to determine the design feasibility of a process/device/system. Please determ
Sladkaya [172]

Answer:

Detailed step wise solution is given below:

6 0
3 years ago
Refrigerant-134a is to be cooled by water in a condenser. The refrigerant enters
KonstantinChe [14]

Answer:

Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37

Background image

I only know this

sorry for errors

4 0
3 years ago
Https://screenshot.best/2QA8H0<br><br><br><br><br><br> Check screen shot
kobusy [5.1K]

Answer:

okay checked it

Explanation:

5 0
3 years ago
A material with a yield strength of 40 kpsi and an endurance strength of 20 kpsi is intended for an application with a von Mises
wlad13 [49]

To solve this problem we will apply the concepts related to Soderberg's relation, which will allow us to find the safety factor based on yield stress, endurance strength, the mean and average stress. The mean and average stress values can be found through the alternating Stress previously given. We will proceed by defining the known values, that is

Yield stress \sigma_y = 40ksi

Endurance strength \sigma_e = 20ksi

The two values for alternating stress are

\sigma_1 = 17ksi

\sigma_2 = 3ksi

We know that mean stress is

\sigma_m = \frac{\sigma_1+\sigma_2}{2}

\sigma_m = \frac{17+3}{2} = 10ksi

And the average stress is

\sigma_v = \frac{\sigma_1-\sigma_2}{2}

\sigma_v = \frac{17-3}{2} = 7ksi

According to Soderberg relation

\frac{1}{F.s} = \frac{\sigma_m}{\sigma_y}+\frac{\sigma_v}{\sigma_e}

\frac{1}{F.s} = \frac{10}{40}+\frac{7}{20}

\frac{1}{F.s} = 0.6

F.s = 1.66 \approx 2

Therefore the factor of safety is 2

3 0
3 years ago
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