Answer:
The solution code is written in Python.
- def largest3(num1, num2, num3):
- largest = num1
- if(largest < num2):
- largest = num2
-
- if(largest < num3):
- largest = num3
-
- return largest
- first_num = int(input("Enter first number: "))
- second_num = int(input("Enter second number: "))
- third_num = int(input("Enter third number: "))
- largest_number = largest3(first_num, second_num, third_num)
- print("The largest number is " + str(largest_number))
Explanation:
<u>Create function largest3</u>
- Firstly, we can create a function <em>largest3 </em>which take 3 numbers (<em>num1, num2, num3</em>) as input. (Line 1).
- Please note Python uses keyword <em>def </em>to denote a function. The code from Line 2 - 10 are function body of <em>largest3</em>.
- Within the function body, create a variable,<em> largest</em>, to store the largest number. In the first beginning, just tentatively assign<em> num1 </em>to<em> largest</em>. (Line 2)
- Next, proceed to check if the current "<em>largest</em>" value smaller than the<em> num2 </em>(Line 4). If so, replace the original value of largest variable with <em>num2</em> (Line 5).
- Repeat the similar comparison procedure to<em> </em><em>num3</em> (Line 7-8)
- At the end, return the final value of "<em>largest</em>" as output
<u>Get User Input</u>
- Prompt use input for three numbers (Line 13 -15) using Python built-in <em>input</em> function.
- Please note the input parts of codes is done outside of the function <em>largest3</em>.
<u>Call function to get largest number and display</u>
- We can simply call the function<em> largest </em>by writing the function name <em>largest</em> and passing the three user input into the parenthesis as arguments. (Line 17)
- The function <em>largest </em>will operate on the three arguments and return the output to the variable <em>largest_number</em>.
- Lastly, print the output using Python built-in <em>print</em> function. (Line 18)
- Please note the output parts of codes is also done outside of the function<em> largest3</em>.
Answer:
False......................
Answer:
Total wight =640.7927 KN
Explanation:
Given that
do= 61 cm
L =120
t= 0.9 cm
That is why inner diameter of the pipe
di= 61 - 2 x 0.9 cm
di=59.2 cm
Water density ,ρ = 1 kg/L = 1000 kg/m³
Weight of the pipe ,wt = 2500 N/m
wt = 2500 x 120 N = 300,000 N
The wight of the water
wt ' = ρ V g
wt'=340792.47 N
That is why total wight
Total wight = wt + wt'
Total wight =300,000+ 340792.47 N
Total wight =640,792.47 N
Total wight =640.7927 KN
Answer:
The youth hockey training facility
Explanation:
